a) Using the depletion approximation and C = dQs/dV, derive Eq (7.12) in the Semiconductor Device Fundamentals textbook: 2 NB(x) = qK EgA²d(1/C})/dv Note that under the depletion approximation Qs = QANBW (assuming a one-side junction), where W is the depletion region width on the lightly doped side. Also recall that the reverse- biased capacitance C = C, : W
a) Using the depletion approximation and C = dQs/dV, derive Eq (7.12) in the Semiconductor Device Fundamentals textbook: 2 NB(x) = qK EgA²d(1/C})/dv Note that under the depletion approximation Qs = QANBW (assuming a one-side junction), where W is the depletion region width on the lightly doped side. Also recall that the reverse- biased capacitance C = C, : W
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Derive the equation for doping profile of a one sided junction using depletion approximation. The full question is attached as an image below
![**a) Using the depletion approximation and \( C = dQ_s/dV \), derive Eq (7.12) in the Semiconductor Device Fundamentals textbook:**
\[
N_B(x) = \frac{2}{qK_s\varepsilon_0A^2 d(1/C_J^2)/dV}
\]
Note that under the depletion approximation \( Q_s = qAN_BW \) (assuming a one-side junction), where \( W \) is the depletion region width on the lightly doped side. Also recall that the reverse-biased capacitance \( C = C_J = \frac{K_s\varepsilon_0A}{W} \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F677ce5ab-ee59-49dd-a3d9-93fdd10daadf%2Ffc521731-6ad2-4f80-a974-91606cab64a3%2Fjkc4s7b_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**a) Using the depletion approximation and \( C = dQ_s/dV \), derive Eq (7.12) in the Semiconductor Device Fundamentals textbook:**
\[
N_B(x) = \frac{2}{qK_s\varepsilon_0A^2 d(1/C_J^2)/dV}
\]
Note that under the depletion approximation \( Q_s = qAN_BW \) (assuming a one-side junction), where \( W \) is the depletion region width on the lightly doped side. Also recall that the reverse-biased capacitance \( C = C_J = \frac{K_s\varepsilon_0A}{W} \).
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