A Using Ohm's and Kirchhoffrs Laws, solve the circuit: Show your formulas 1- 25 mA VI = %3D V2 A + R, V3 = 680 2 V4= 45 V 1502 R2 R4 = %3D 750 2 RT = VA = R4 R, VBD= Vc%= R1 2) Solve for and show your formulas: R2 RT = Vs = P2= 0.5 W R = %3D R2 = %3D Pr =2 W I2 = 200 mA D.
A Using Ohm's and Kirchhoffrs Laws, solve the circuit: Show your formulas 1- 25 mA VI = %3D V2 A + R, V3 = 680 2 V4= 45 V 1502 R2 R4 = %3D 750 2 RT = VA = R4 R, VBD= Vc%= R1 2) Solve for and show your formulas: R2 RT = Vs = P2= 0.5 W R = %3D R2 = %3D Pr =2 W I2 = 200 mA D.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:Name:
A Using Ohm's and Kirchhoff's Laws, solve the circuit: Show your formulas I= 25 mA
VI =
V2 =
+ R
V3 =
680 2
V4 =
45 V
1502 R2
RA =
7502
RT =
VA =
R4
R3
C
VBD =
Vc =
R1
2)
Solve for and show your
formulas:
R2
RT =
Vs =
P2 = 0.5 W
R1
R2
I =
Pr =2 W
I2 =
%3D
200 mA
II
Expert Solution

Step 1
Electric circuits are closed-loop or route networks of electrical components through which electrons can flow. This route is composed of electrical cables and is powered by an external source, such as a battery. The point at which electrons begin to flow is referred to as the source, while the point at which electrons exit the electrical circuit is referred to as the return.
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