TABLE 20.1 Standard Reduction Potentials in Water at 25°CPotential (V)Reduction Half-ReactionF2(g) + 2 eMnO4 (aq) + 8 H*(aq) + 5 e¯Cl2(8) + 2 eCr20,2 (aq) + 14 H*(aq) + 6 e-O2(g) + 4 H*(aq) + 4 eBr2(1) + 2 eNO3 (aq) + 4 H" (ад) + 3еAg*(aq) + e¯Fe (aq) + e¯O2(g) + 2 H*(aq) + 2 e¯MnO4 (aq) + 2 H2O(1) + 3 e¯I2(s) + 2 eO2(8) + 2 H2O(1) + 4 e¯Cu²“(aq) + 2 e2 H"(ag) + 2 еNi2+(aq) + 2 eFe2*(aq) + 2 eZn"(aq) + 2 e2 H20(1) + 2 eAl3+(ag) + 3 eNa*(aq) + e¯Li*(aq) + e+2.872 F (aq)+1.51Mn2+(aq) + 4 H2O(1)+1.36→ 2 CI (aq)2 Cr* (aq) + 7 H2O(!)2 H2O(1).3++1.33>+1.23+1.06→ 2 Br (aq)+0.96NO(g) + 2 H2O(1)Ag(s)Fe2*(aq)+0.80>3++0.77>H2O2(aq)MnO2(s) + 4 OH (aq)+0.68+0.59>+0.5421 (aq)+0.40→ 4 OH (aq)+0.34→ Cu(s)0 [defined]H2(g)Ni(s)→ Fe(s)-0.28-0.442+-0.76Zn(s)H2(g) + 2 OH (aq)→ Al(s)Na(s)-0.83-1.66-2.71-3.05Li(s)Copyright © 2006 Pearson Prentice Hall, Inc. a) Using data in Table 20.1, calculate the standard emffor a cell that employs thefollowing overall cell reaction:2 Al(s) + 3 I2(s) →2 Al3+(aq) + 6 I (aq)b) Calculate the emfgenerated by the same cell when [Al3+] = 4.0 x 10-3 M and [I-] =0.010 M.

The question is based on the concept of electrochemistry. the electrode which has higher reduction…

a) Using data in Table 20.1, calculate the standard emf for a cell that employs the following overall cell reaction: 2 Al(s) + 3 I2(s) - 2 Al3+(aq) + 6 I (aq) b) Calculate the emf generated by the same cell when [Al3+] = 4.0 x 10-3 M and [I] = 0.010 M.

a) Using data in Table 20.1, calculate the standard emf for a cell that employs the following overall cell reaction: 2 Al(s) + 3 I2(s) - 2 Al3+(aq) + 6 I (aq) b) Calculate the emf generated by the same cell when [Al3+] = 4.0 x 10-3 M and [I] = 0.010 M.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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