(a) Using a loop structure, rewrite the above pseudocode two times: Once in Python and another in either C or Java.
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(a) Using a loop structure, rewrite the above pseudocode two times: Once in Python and
another in either C or Java.
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- For the C code int dw_loop(long x) { long y = x* x; long 'p - &x; long n - 2*x do { x += y; (*p)++; n--; } while (n > 0); return x; }Q4: 4- for (A=[8 -3 4 5 9), we can assign (9) using: a) min(a) b) max(a) c) a (end) d) None of themle.com/forms/d/e/1FAlpQLSc6PlhZGOLJ4LOHo5cCGEf9HDChfQ-tT1bES-BKgkKu44eEnw/formResponse The following iterative sequence is defined for the set of positive integers: Sn/2 3n +1 ifn is odd if n is even Un = Using the rule above and starting with 13, we generate the following sequence: 13 u13 = 40 u40 =20 u20 = 10→ u10 =5 u5 = 16 u16 = 8 ug = 4 → Us =2 u2 =1. It can be seen that this sequence (starting at 13 and finishing at 1) contains 10 terms. The below function takes as input an integer n and returns the number of terms generated by the sequence starting at n. function i-Seq (n) u=n; i=%3; while u =1 if statement 1 u=u/2; else statement 2 end i=i+1; end statement 1 and statement 2 should be replaced by: None of the choices statement 1 is "mod(u,2)=D%3D0" and statement 2 is "u = 3*u+1;" statement 1 is "u%2" and statement 2 is "u = 3*u+1;" O statement 1 is "mod(n,2)=30" and statement 2 is "u = 3*n+1;"
- c(n)=10*c(n-1),c(1)=3Exercise H for the Nested Loop Nested Loop Problems Write the program that would generate the multiplication table for numbers 1 to 10. For example: Result 1 2 3 4 5 6 7 8 9 10 2 4 6 8 10 12 14 16 18 20 3 6 9 12 15 18 21 24 27 30 4 8 12 16 20 24 28 32 36 40 5 10 15 20 25 30 35 40 45 50 6 12 18 24 30 36 42 48 54 60 7 14 21 28 35 42 49 56 63 70 8 16 24 32 40 48 56 64 72 80 9 18 27 36 45 54 63 72 81 90 10 20 30 40 50 60 70 80 90100x <- bubblesort(sample(1:6, size=5, replace=T)) if (x[1]==x[5]){ hand <-"Yahtzee" } else if (x[1]==x[4] ] x[2]==x[5]) { hand <- "4ofKind" } } else { hand <-"Chance" } The above code lays this out for Yahtzee and 4 of a kind. Find statements that work for the rest and put this into a function called get hand , which returns what type of hand was rolled from a sorted roll of five dice. Make sets of rolls and test them to make sure they work. Note that above we use an else if, which allows us to test multiple conditions in an if-else statement.
- Fjul BasicGiven the following pseudocode: function fun2(n) { var outer_count = 0; var inner_count %3D for (i=0; i 0, as an expression of normal arithmetic and n, what is the value of outer_count that counts the number of times the outer loop executes? Enter an expression Fun.2.inner: Assuming n E N and n > 0, as an expression of normal arithmetic and n, what is the value of inner_count that counts the number of times the inner loop executes? Enter an expressionWrite in C Language Spilitology Yosef is a peculiar fellow. He introduced the idea to study a string by splitting it into two, and he called it Splitology. Why split a string? We do not know. Didn’t we say that Yosef is a weird one? Yosef is interested in one particular type of string, a palindrome. A palindrome is a string that is the same for both forwards and backwards. Example of palindrome strings are “ada”, “taat”, and “radar”. On the other hand, string such as “taman” is not a palindrome; notice that “taman” becomes “namat” if read backwardsand it’s not the same as “taman”. As the idea of Splitology is still new, Yosef is investigating whether a string can be split into two non-empty strings such that each string is a palindrome. For example, the string “malamini” can be split into “malam” and “ini” while both of them are palindrome. Another example is “ababab”. It can be split into “aba” and “bab”, and both of them are palindrome. Note that “ababab” can also be split into…