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(a) Use Gauss-Jordan elimination to solve the following homogeneous system. Enter æ1 , 22, 13 in the most general form. If necessary use parameters s and t, so your answer would look something like (s,2*s,s) or (s-2*t,s,0). xi +22 – 2 x3 = 0 2 x1 +3 x2 – 3 x3 = 0 -*1 +22 +4 23 = 0 %3D - %3D (b) Find by inspection a particular solution of the following system x1 +x2 – 2 x3 = 2 2 x1 +3 x2 – 3 x3 = 5 -a1 + 22 +4 13 = 0 %3D and hence write down the general solution, using your results from part (a).

(a) Use Gauss-Jordan elimination to solve the following homogeneous system. Enter æ1 , 22, 13 in the most general form. If necessary use parameters s and t, so your answer would look something like (s,2*s,s) or (s-2*t,s,0). xi +22 – 2 x3 = 0 2 x1 +3 x2 – 3 x3 = 0 -*1 +22 +4 23 = 0 %3D - %3D (b) Find by inspection a particular solution of the following system x1 +x2 – 2 x3 = 2 2 x1 +3 x2 – 3 x3 = 5 -a1 + 22 +4 13 = 0 %3D and hence write down the general solution, using your results from part (a).

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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(a) Use Gauss-Jordan elimination to solve the following homogeneous system. Enter æ1 , 22, 13 in the most general form. If necessary use parameters s and t, so your answer would look something like (s,2*s,s) or (s-2*t,s,0). xi +22 – 2 x3 = 0 2 x1 +3 x2 – 3 x3 = 0 -*1 +22 +4 23 = 0 %3D - %3D (b) Find by inspection a particular solution of the following system x1 +x2 – 2 x3 = 2 2 x1 +3 x2 – 3 x3 = 5 -a1 + 22 +4 13 = 0 %3D and hence write down the general solution, using your results from part (a).
Transcribed Image Text:(a) Use Gauss-Jordan elimination to solve the following homogeneous system. Enter æ1 , 22, 13 in the most general form. If necessary use parameters s and t, so your answer would look something like (s,2*s,s) or (s-2*t,s,0). xi +22 – 2 x3 = 0 2 x1 +3 x2 – 3 x3 = 0 -*1 +22 +4 23 = 0 %3D - %3D (b) Find by inspection a particular solution of the following system x1 +x2 – 2 x3 = 2 2 x1 +3 x2 – 3 x3 = 5 -a1 + 22 +4 13 = 0 %3D and hence write down the general solution, using your results from part (a).
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