A university wants to know all course names of sections that student Cam Sato has enrolled in.Instructor•InstructorIDSection Instructor• SectionIDSection⚫SectionIDEnrollment⚫ SectionIDStudent⚫ StudentIDFirstName• InstructorIDLastNameAcademicRankCourseIDTermStudentIDCapacitySalaryCourse•CourseIDFirstNameLastNameEmailAddressBirthDateNameDescriptionThe query below answers the university's question. Fill in the blanks.SELECT DISTINCT C.NameFROM ___ (A)___(B) Section SE ON C.CourseID =SE.CourseIDINNER JOIN Enrollment E ON SE.SectionID = E. SectionIDINNER JOIN Student ST ON E.StudentID = _ (C)_____WHERE ST. FirstName = 'Cam' AND ST. LastName = 'Sato';Credits(A) Ex: Keyword1 @O

The SQL query provided is designed to retrieve the distinct course names for the sections in which…

Answered: A university wants to know all course…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Task 1: ' The Car Maintenance team wanted to ensure that the default price of the maintenance actions should not be empty and 0 instead if not specified. Alter the MAINTENANCE_TYPES table created in Chapter 8, Activity 1 to set the default MAINTENANCE_PRICE to 0. ANSWER IN MYSQL PLEASE
SQL
Task 6: The Car Maintenance team considered that the available maintenance tasks should also have the price information in the database. Alter the MAINTENANCE_TYPES table to include a new column named MAINTENANCE_PRICE of type FLOAT. ANSWER IN MYSQL PLEASE
Please refer to the following diagram for Q19 to Q20. PERSON PK P_ID P_LNAME P_FNAME ΕMPLOYΕ P_ID EMP_HIRE_DATE STUDENT P ID STUDY ΜAIOR PK, FK1 PK, FK1 19. Which of the following statements is/are true? (1) A Person must be either a Student or an Employee. (2) A Person can neither be a Student nor an Employee. (3) A Person must be a Student or an Employee or both. a. (1) only b. (3) only c. (1) and (2) only d. (1), (2) and (3).
DO NOT COPY FROM OTHER WEBSITES Correct and detailed answer will be Upvoted else downvoted. Also explain why other options are FALSE. Thank you!
Task 2: ' The Driver Relationship team wants to ensure that the all driving license IDs in the active drivers table have the length of 7. Alter the ACTIVE_DRIVERS table created in Chapter 8, Activity 1 to check the length of the DRIVER_DRIVING_LICENSE_ID.
DATABASE
How many times has each language been used in films? Return the value for all six languages. Display: language name and the number of films
1.What is the result when the following SQL query is executed on a table named products? Choose the most correct answer. SELECT AVG(Products)FROM Products; Group of answer choices The query results in an error because the is no AVG function None of the above The query results in an error be cause a column is not specified The query returns the average of the Products table 2. If the primary key in the Employee table is located in the "ID" column what is the maximum number of results the following SQL SELECT query will return? SELECT *FROM EmployeeWHERE ID = 15; Group of answer choices 2 1 3 Do not have enough information to determine the answer 0
Student Subject STU_number STU_Name Registration SUB_Code STU_Number SUB_Name STU_Suname STU DOB SUB_Code SUB_Credt Final_Mark LEC_ID Lecturer Department LEC_ID DEP_ID LEC_NAme DEP_Name LEC_Tle DEP Location DEP_ID The following queries must be answered with a SQL statement. Provide the code. 5.1 How many students are registered for each subject? 5.2 What is the average number of subjects each student has? 5.3 Which student(s) has achieved the highest mark? Display the name of the student(s) and the subject with the mark. 5.4 Which department(s) has the most lecturers? Display the name of the department(s) and the number of lecturers 5.5 Display all the subjects with less than 25 students.
Goals for the design of the logical schema include
Open the Missing Addresses query in Design view. Add a new column to determine if a customer does not have an address on file. If the customer’s Address is null, it should display Missing. If not, it should display nothing. Name the column AddressPresent. Add criteria of Missing to the column you just created, so only the customers missing an address display. Move the AddressPresent field so it appears between PhoneNumber and Address. Run the query. Ensure only customers with null Address fields display. Save and close the query.

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