A university department chair believes that the afternoon section of a large survey class has a consistently higherproportion of students that pass the class compared to the morning section. The chair checks a random sampleof student records from each section. The results of the data collected are shown below.Morning sectionSuccessesObservationsProportionConfidence levelZ-scorep-valueAfternoon section419 Successes500 Observations0.838 Proportion95%2.3660.00895326000.887-3-2=Morning section samples: M Ex: 9Afternoon section samples: nA =Sample proportion for morning section samples: ÎM = Ex: 1.234Sample proportion for afternoon section samples: PA-10P= Ex: 1.2342=||123

The given output is, The morning section samples is, nM=500 The afternoon section samples is,…

Answered: A university department chair believes…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Twenty-eight college faculty at Acme Looniversity who volunteered for a fitness program were divided into low-fitness and high-fitness groups based on a physical examination. The subjects then took a Personality Factor Questionnaire. Below are the data for the "ego strength" measurement based on the questionnaire. Acme Looniversity Data Group Fitness Sample size Average Standard deviation 1 Low 14 4.6 0.69 2 High 14 6.4 0.43 Assuming the data for Group 1 and 2 are independent of each other and are both normally distributed, compute a 90% confidence interval for the difference between the two means. Round your answer to 3 decimal places. What conclusion can you draw? Group of answer choices (-2.173,-1.427), Group 1 is bigger (-1.923,-1.677), Group 2 is bigger (-2.173,-1.427), Group 2 is bigger (-1.923,-1.677), no conclusion (-1.923,-1.677), Group 1 is bigger
question 4 and 5
Justice in the Courts? In an issue of Parade Magazine, the editors reported on a national survey on law and order. One question asked of the 2512 U.S. adults who took part was whether they believed that juries “almost always” convict the guilty and free the innocent. Only 578 said that they did. At the 5% significance level, do the data provide sufficient evidence to conclude that less than one in four Americans believe that juries “almost always” convict the guilty and free the innocent?
B. A sample data has a distribution that has a single mode and is strongly positively skewed. An analyst computes three measures of location for this data; the mean, the median and mode. (i) State the largest of these three location measures. (ii) Suggest, with a reason, which would be the best measure of location.
Pages were randomly selected from The Bear and the Dragon by Tom Clancy, Harry Potter and the Sorcerer's Stone by J.K. Rowling, and War and Peace by Leo Tolstoy. The Flesch Reading Ease scores for those pages are listed below. Use a 0.05 significance level to test the claim that the three samples are from populations with the same mean. Clancy 58.2 73.4 73.1 64.4 72.7 89.2 43.9 76.3 76.4 78.9 69.4 72.9 Rowling 85.3 84.3 79.5 82.5 80.2 84.6 79.2 70.9 78.6 86.2 74.0 83.7 Part (B) Identify the test statistic and the P-value The test statistic F= The P-value is notation.) Tolstoy 69.4 64.2 71.4 71.6 68.5 51.9 72.2 74.4 52.8 58.4 65.4 73.6 (Round to four decimal places.) (Round to six decimal places. Do not use scientific
Report an appropriate hypothesis test for a positive linear relationship and use a 5% significance level. Explain the potential error in words, in context. In the answer options below I have used the phrase “a certain relationship” because I don’t want to give away exactly what type of relationship it is. Group of answer choices We would be accepting that there was a certain relationship between Sale amount and Tip when actually there wasn’t. We would not be accepting that there was a certain relationship between Sale amount and Tip when indeed there wasn’t. We would not be accepting that there was a certain relationship between Sale amount and Tip when actually there was. We would be accepting that there was a certain relationship between Sale amount and Tip when indeed there was.
A college administrator is interested in determining the proportion of students who receive some sort of financial aid. Instead of examining the records for all students, the administrator randomly draws 120 students and finds that 48 of them are receiving financial aid. Use a 90% confidence interval to estimate the true proportion of students who receive financial aid.
The National Association of Colleges and Employers sponsors the Graduating Student and Alumni Survey.Part of the survey gauges student optimism in landing a job after graduation. According to one year’s surveyresults, published in American Demographics, among the 1218 respondents, 733 said that they expecteddifficulty finding a job. Construct a 90% confidence interval for the proportion of students who expecteddifficulty finding a job. Interpret your result.
A political scientist claims that 38% of first-year college students characterize themselves as being “moderate” or “middle of the road” as far as their political affiliation is concerned. Believing this claimed value is too high, you survey a random sample of 400 first-year college students and find that 120 characterize themselves as being “moderate” or “middle of the road.” Based on this information, what will the test statistic be? Choose the answer below that is closest to what you calculate, and try not to do a lot of rounding until you get to the very end of your calculations. 1. -0.3 2. -1.2 3. -2.6 4. -3.3 5. None of the other answer options are correct because the test statistic should be positive, not negative.
Subject: accounting
The customer service ratings for two banks are found below. As manager decide which bank your company should select using a 90% confidence level. Conduct a test to determine whether there is a significant difference between the variances of the two banks' rating. Current New Bank 89.9 80.4 82.2 98.7 75.1 83.1 41.7 99.8 84.3 86.2 98.6 97.1 75.4 87.9 80.6 78.5 76.4 69.9 81.4 98.5 59.7 82.9 98.4 49.5 83.4 54.6 76.2 90.1 1. Provide the null hypothesis:. a. Ho: o?, s o2, b. Họ: o?, 2 o?2 c. Ho: o?, = o?2 d. Ho: o?, * o?2 2. Compute the test statistic (Round to the second decimal place) 3. Determine the p-value (Round to the third decimal place) 4. What do you conclude 5. What would you recommend

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