A uniformly charged insulating rod of length 13.0 cm is bent into the shape of a semicircle as shown in the figure below. The rod has a total charge of -7.50 µC. (a) Find the magnitude of the electric field (in N/C) at o, the center of the semicircle. N/C (b) Find the direction of the electric field at o, the center of the semicircle. O to the left O to the right O upward O downward O into the page O out of the page (c) What if? What would be the magnitude of the electric field (in N/C) at O if the top half of the semicircle carried total charge of -7.50 µC and the bottom half, insulated from the top half, carried a total charge of +7.50 µC? N/C (d) What would be the direction of the electric field at O if the top half of the semicircle carried a total charge of -7.50 µC and the bottom half, insulated from the top half, carried a total charge of +7.50 µC? O to the left O to the right O upward O downward O into the page O out of the page

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Chapter1: Units, Trigonometry. And Vectors
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A uniformly charged insulating rod of length 13.0 cm is bent into the shape of a semicircle as shown in the figure below. The rod has a total charge of -7.50 µC.
•0
(a) Find the magnitude of the electric field (in N/C) at O, the center of the semicircle.
N/C
(b) Find the direction of the electric field at 0, the center of the semicircle.
O to the left
O to the right
upward
O downward
O into the page
O out of the page
(c) What if? What would be the magnitude of the electric field (in N/C) at O if the top half of the semicircle carried a total charge of -7.50 µC and the bottom half, insulated from the top half, carried a total charge of +7.50 µC?
N/C
(d) What would be the direction of the electric field at O if the top half of the semicircle carried a total charge of -7.50 µC and the bottom half, insulated from the top half, carried a total charge of +7.50 µC?
O to the left
O to the right
upward
O downward
O into the page
O out of the page
Transcribed Image Text:A uniformly charged insulating rod of length 13.0 cm is bent into the shape of a semicircle as shown in the figure below. The rod has a total charge of -7.50 µC. •0 (a) Find the magnitude of the electric field (in N/C) at O, the center of the semicircle. N/C (b) Find the direction of the electric field at 0, the center of the semicircle. O to the left O to the right upward O downward O into the page O out of the page (c) What if? What would be the magnitude of the electric field (in N/C) at O if the top half of the semicircle carried a total charge of -7.50 µC and the bottom half, insulated from the top half, carried a total charge of +7.50 µC? N/C (d) What would be the direction of the electric field at O if the top half of the semicircle carried a total charge of -7.50 µC and the bottom half, insulated from the top half, carried a total charge of +7.50 µC? O to the left O to the right upward O downward O into the page O out of the page
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