I need help solving this problem, thank you! A uniform rod of length L and mass M is free to rotate on africtionless pin through one end. The rod is released fromrest in the horizontal position.а.Draw the FBD of the rod when it is in a horizontalposition after the person lets go.b. What is the initial torque on the system?What is the initial angular velocity and angularacceleration of the system?d. What is the initial angular momentum of the system?PivotMgС.e. What is the angular velocity of the rod at its lowest position? Because there is no friction, energyis conserved.f. What is the linear speed (in m/s) of the CM of the rod and the linear speed of the lowest pointon the rod when the rod is vertical?g. What is the angular momentum of the rod when it is vertical?h. Why is this angular momentum not equal to the angular momentum when the rod is horizontal?What is causing the change in angular momentum?

Since you have posted a question with multiple sub-parts, we will solve the first three subparts for you. To get the remaining sub-part solved please repost the complete question and mention the sub-parts to be solved. (a) Free Body Diagram (b) Torque acting on the system, the product of the force applied to the system and perpendicular distance. τ=F·d⊥τ=Mg·L2τ=MgL2 This is the initial torque acting on the system. (c) Initial angular acceleration on the system τ=Iα∵ Iα=MgL2ML23α=MgL2α=3g2L Initial angular velocity on the system is ω=αtω=3g2Ltω=3gt2L

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A uniform rod of length L and mass M is free to rotate on a frictionless pin through one end. The rod is released from rest in the horizontal position. а. Draw the FBD of the rod when it is in a horizontal position after the person lets go. b. What is the initial torque on the system? What is the initial angular velocity and angular acceleration of the system? d. What is the initial angular momentum of the system? Pivot С. Mg What is the angular velocity of the rod at its lowest position? Because there is no friction, energy is conserved. What is the linear speed (in m/s) of the CM of the rod and the linear speed of the lowest point on the rod when the rod is vertical? g. What is the angular momentum of the rod when it is vertical? h. Why is this angular momentum not equal to the angular momentum when the rod is horizontal? What is causing the change in angular momentum? е. f.

A uniform rod of length L and mass M is free to rotate on a frictionless pin through one end. The rod is released from rest in the horizontal position. а. Draw the FBD of the rod when it is in a horizontal position after the person lets go. b. What is the initial torque on the system? What is the initial angular velocity and angular acceleration of the system? d. What is the initial angular momentum of the system? Pivot С. Mg What is the angular velocity of the rod at its lowest position? Because there is no friction, energy is conserved. What is the linear speed (in m/s) of the CM of the rod and the linear speed of the lowest point on the rod when the rod is vertical? g. What is the angular momentum of the rod when it is vertical? h. Why is this angular momentum not equal to the angular momentum when the rod is horizontal? What is causing the change in angular momentum? е. f.