A uniform random variable X has a probability density given by: 1/0≤x≤2 otherwise f(x) = The mean of X is 1 and variance is 1/3. (a) Find the probability that X takes values within 2 standard deviations of the mean i.e. P(|X−1| < 20). (b) Find a bound for the probability in part (a) using the Chebychev's inequality.
A uniform random variable X has a probability density given by: 1/0≤x≤2 otherwise f(x) = The mean of X is 1 and variance is 1/3. (a) Find the probability that X takes values within 2 standard deviations of the mean i.e. P(|X−1| < 20). (b) Find a bound for the probability in part (a) using the Chebychev's inequality.
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
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![**Uniform Random Variable Analysis**
A uniform random variable \( X \) has a probability density given by:
\[
f(x) =
\begin{cases}
\frac{1}{2} & \text{for } 0 \leq x \leq 2 \\
0 & \text{otherwise}
\end{cases}
\]
The **mean** of \( X \) is 1, and the **variance** is \( 1/3 \).
**Tasks**
(a) Find the probability that \( X \) takes values within 2 standard deviations of the mean, i.e., \( P(|X - 1| < 2\sigma) \).
(b) Find a bound for the probability in part (a) using the Chebychev's inequality.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcf673b33-84d3-4207-a3d8-77b439e8ab65%2Fde753bd7-7686-4bc4-a111-54b008e25ae2%2Fu6e9uea_processed.png&w=3840&q=75)
Transcribed Image Text:**Uniform Random Variable Analysis**
A uniform random variable \( X \) has a probability density given by:
\[
f(x) =
\begin{cases}
\frac{1}{2} & \text{for } 0 \leq x \leq 2 \\
0 & \text{otherwise}
\end{cases}
\]
The **mean** of \( X \) is 1, and the **variance** is \( 1/3 \).
**Tasks**
(a) Find the probability that \( X \) takes values within 2 standard deviations of the mean, i.e., \( P(|X - 1| < 2\sigma) \).
(b) Find a bound for the probability in part (a) using the Chebychev's inequality.
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