A uniform horizontal beam of weight 371 Nand length 2.85 m has two weights hangingfrom it.One weight of 271 N is located0.7296 m from the left end; the other weightof 171 N is located 0.7296 m from the rightend.What must be the magnitude of the oneadditional force on the beam that will produceequilibrium?Answer in units of N. At what distance from the left end must thisforce be applied for the beam to be in equilib-rium?Answer in units of m.

For equilibrium net force on the beam should be zero.

A uniform horizontal beam of weight 371 N and length 2.85 m has two weights hanging from it. 0.7296 m from the left end; the other weight of 171 N is located 0.7296 m from the right end. One weight of 271 N is located What must be the magnitude of the one additional force on the beam that will produce equilibrium? Answer in units of N.

A uniform horizontal beam of weight 371 N and length 2.85 m has two weights hanging from it. 0.7296 m from the left end; the other weight of 171 N is located 0.7296 m from the right end. One weight of 271 N is located What must be the magnitude of the one additional force on the beam that will produce equilibrium? Answer in units of N.