A uniform electric field points in the :-direction, E = Ek. By explicitly calculating the surface integral Sf, E- dS, show that the flux of E through the surface s= {(z.y. 2) €R* :+ y² + = a°, =>0} (as shown in the diagram), is given by Eza". Comment on why this is to be expected.
A uniform electric field points in the :-direction, E = Ek. By explicitly calculating the surface integral Sf, E- dS, show that the flux of E through the surface s= {(z.y. 2) €R* :+ y² + = a°, =>0} (as shown in the diagram), is given by Eza". Comment on why this is to be expected.
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Transcribed Image Text:A uniform electric field points in the :-direction, E = Ek. By explicitly calculating the surface
integral f, E dS, show that the flux of E through the surface
S= {(z, y, 2) € R* : ²+ y² + s² = a°, z > 0}
(as shown in the diagram), is given by Era". Comment on why this is to be expected.
** y+za
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