A uniform electric field, E = (3.0N/C)j – (4.0N/C)k is going through a rectangular plane of 20 cm² which lies in the xy plane. Find the electric flux through the plane.

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1. A uniform electric field, **E** = (3.0 N/C) *ĵ* − (4.0 N/C) *k̂* is going through a rectangular plane of 20 cm² which lies in the xy plane. Find the electric flux through the plane.
Transcribed Image Text:1. A uniform electric field, **E** = (3.0 N/C) *ĵ* − (4.0 N/C) *k̂* is going through a rectangular plane of 20 cm² which lies in the xy plane. Find the electric flux through the plane.
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Step 1

Given, E=(3.0 N/C)j^ -(4.0N/C)k^ϕE = E·S (1)S is the area vector, where area lies in the xy planeTherefore,S = (20×10-4) k^

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