Please simplify process as much as possible! 1. A uniform electric field, **E** = (3.0 N/C) *ĵ* − (4.0 N/C) *k̂* is going through a rectangular plane of 20 cm² which lies in the xy plane. Find the electric flux through the plane.

Given, E→=(3.0 N/C)j^ -(4.0N/C)k^ϕE = E→·S→ —(1)S→ is the area vector, where area lies in the xy…

Answered: A uniform electric field, E = (3.0N/C)j…

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Please simplify process as much as possible!

1. A uniform electric field, **E** = (3.0 N/C) *ĵ* − (4.0 N/C) *k̂* is going through a rectangular plane of 20 cm² which lies in the xy plane. Find the electric flux through the plane.

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$G i v e n, \vec{E} = (3.0 N / C) \hat{j} - (4.0 N / C) \hat{k} ϕ_{E} = \vec{E} \cdot \vec{S} — (1) \vec{S} i s t h e a r e a v e c t o r, w h e r e a r e a l i e s i n t h e x y p l a n e T h e r e f o r e, \vec{S} = (20 \times 10^{- 4}) \hat{k}$

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A uniform electric field, E = (3.0N/C)j – (4.0N/C)k is going through a rectangular plane of 20 cm² which lies in the xy plane. Find the electric flux through the plane.