A uniform beam of mass 138 kg and length 7 m is pinned at its left end so that it is free to rotate about that end. Its right end rests against a vertical, slippery wall such that the beam makes a 57 degree angle with the horizontal. Calculate the normal force the vertical wall exerts on the beam, in N. Even though the force points to the left your answer should be a positive number. (Please answer to the fourth decimal place - i.e 14.3225)
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A uniform beam of mass 138 kg and length 7 m is pinned at its left end so that it is free to rotate about that end. Its right end rests against a vertical, slippery wall such that the beam makes a 57 degree angle with the horizontal. Calculate the normal force the vertical wall exerts on the beam, in N. Even though the force points to the left your answer should be a positive number.
(Please answer to the fourth decimal place - i.e 14.3225)
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- Problem 2: A uniform beam of length L = 1.9 m and mass M = 49 kg has its lower end fixed to pivot at a point P on the floor, making an angle 0 = 15° as shown in the digram. A horizontal cable is attached at its upper end B to a point A on a wall. A box of the same mass M as the beam is suspended from a rope that is attached to the beam one-fourth L from its upper end. M M.A 2.00-m-long, 500 kg steel uniform beam extends horizontally from the point where it has been bolted to the framework of a new building under construction. A 70 kg construction worker stands at the far end of the beam. What is the magnitude of the torque about the bolt due to the worker and the weight of the beam?Fy Ex The plant in the picture has mass of 30 kg, and is hanging at a distance of 1.8 meters from the wall. The horizontal rod has mass of 7.8 kg. Assume that its weight is evenly distributed, therefore it can be treated as a single force at the center of mass. The rod is 2 meters long, and there is a cable at a 38° angle supporting it at the end. Using the wall as the axis of rotation, find the magnitude of the downward torque, from both the weight of the rod and the weight of the plant.
- A woman applies a torque to a nut with a wrench 0.250 m long. Because of the cramped space, she must exert a force upward at an angle of 70.0° with respect to a line from the nut through the end of the wrench. If the force she exerts has magnitude 46.0 N, what magnitude torque (in N · m) does she apply to the nut? (Assume that the force is applied at the end of the wrench.)Two forces, F1=100 N (Newton) and F2=20N, are applied on opposite sides of a door's knob at angles theta_1=30 degrees and theta_2=60 degrees respectively, causing the door to rotate (about the axis passing though its hinges). If the distance from the knob to the rotation axis is 0.8 meter, find the net torque exerted on the door and specify the direction of rotation of the door (in this problem, assume that the force F1 causes a counterclockwise rotation and F2 a clockwise rotation). A.) Net Torque = 26.14 N.m; the door rotates counterclockwise. B.) Net Torque = -25.4 N.m; the door rotates counterclockwise. C.) Net Torque = 123.8 N.m; the door rotates clockwise. D.) Net Torque = 1.784 N.m; the door rotates clockwise.A 10.0 m long ladder weighing 50.0 N rests against a smooth vertical wall. If the ladder is just on the verge of slipping when it makes a 50.0° angle with the ground find the coefficient of static friction between the ladder and ground. The ladder is in equilibrium. This means that the torque around ANY pivot point must be zero. In problems like this, you can pick the pivot point of your choice, and still solve for the correct forces. However, there is typically a choice for the pivot point that makes the problem solving steps possible or at least easier. This will depend on the problem, but often depends on the fact that the torque due to a force at the pivot point is zero. This lets you ignore those torque terms in your calculations. a. What is the best choice of pivot point for this problem? Select one: A. The base of the ladder B. The center of mass of the ladder C. The top of the ladder By selecting the base of the ladder, you can ignore the torque due to both the…
- (a) A person opens a 1.20 m wide door by pushing on it with a force of 57.5 N applied at the center of the door, at an angle perpendicular to the door's surface. What magnitude of torque (in N · m) is applied about an axis through the hinges? _________N · m (b) A man opens the same door, using the same force, again directed perpendicular to the surface, but now the force is applied at the edge of the door. What magnitude of torque (in N · m) is applied about the axis through the hinges now? _________N · mFor two existing torques, what third force at a given distance from the pivot will balance them? Imagine a meter stick set up as in the figure. It hangs from a central bracket, and two hanging masses can hang from it from each of their brackets. At a third location, a force probe can either pull up or pull down on the stick, depending on what is needed to balance the stick. The mass of the meter stick is 120 g. sketch the situation (drawing r1, r2, r3, F1, F2, and F3) and determine the magnitude (value) and direction (+ or -) of each torque. Don't include the mass of a bracket that would hold the hanging mass in place; assume the mass listed is the entire mass hanging at that point. For each trial, use the principle of equilibrium (where the sum of torques is zero) to calculate the third, unknown force acting at x3Consider the image below of a wheel that pivots about its center. Force 1 has size 176 N and acts 1.8 m from the center. The angle shown is 36 degrees. Force 2 has size 111 N and acts 0.7 m from the center. The angle shown is 30 degrees. Taking counterclockwise to be positive, calculate the net torque on the wheel, in N m. (Please answer to the fourth decimal place - i.e 14.3225)
- For two existing torques, what third force at a given distance from the pivot will balance them? Imagine a meter stick set up as in the figure. It hangs from a central bracket, and two hanging masses can hang from it from each of their brackets. At a third location, a force probe can either pull up or pull down on the stick, depending on what is needed to balance the stick. The mass of the meter stick is 120 g. sketch the situation (drawing r1, r2, r3, F1, F2, and F3) and determine the magnitude (value) and direction (+ or -) of each torque. Don't include the mass of a bracket that would hold the hanging mass in place; assume the mass listed is the entire mass hanging at that point. For each trial, use the principle of equilibrium (where the sum of torques is zero) to calculate the third, unknown force acting at x3A beam, uniform in mass, M = 51 kg and length L = 6 m, hangs by a cable supported at point B, and rotates without friction around point A. On the end far of the beam, an object of mass m = 12 kg is hanging. The beam is making an angle of θ = 15° at point A with respect to the + x-axis. The cable makes an angle φ = 25° with respect to the - x-axis at B. Assume ψ = θ + φ. Part (a) Select the correct free body diagram. In the figure the tension is T, horizontal and vertical components of the support force are Sx and Sy, FB is the weight of the beam, and Fm is the weight of the mass. Part (b) Find an expression for the lever arm for the weight of the beam, lB, about the point A? Part (c) Find an expression for the lever arm for the weight of the mass, lm? Part (d) Write an expression for the magnitude of the torque about point A created by the tension T. Give your answer in terms of the tension T and the other given parameters and trigonometric functions. Part (e) What is the…