A typical donation of whole blood is equal to a pint (473 ml). If the average density of blood PBLOOD = 1060 kg/m³, what is the mass of donated blood?
A typical donation of whole blood is equal to a pint (473 ml). If the average density of blood PBLOOD = 1060 kg/m³, what is the mass of donated blood?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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
Transcribed Image Text:**Problem: Calculating the Mass of Donated Blood**
A typical donation of whole blood is equal to a pint (473 ml). If the average density of blood, \( \rho_{\text{BLOOD}} = 1060 \, \text{kg/m}^3 \), what is the mass of the donated blood?
**Options:**
- ○ 0.501 kg
- ○ 0.501 g
- ○ 0.501 lb
- ○ 5.01 kg
- ○ 5.01 g
![**Question:**
Atmospheric pressure at sea level is \(101.3 \times 10^3 \, \text{Pa}\). What is the force exerted by the atmosphere on a square foot of area?
**Options:**
- \(101 \, \text{kN}\)
- \(109 \, \text{kN}\)
- \(332 \, \text{kN}\)
- \(30.9 \, \text{kN}\)
- \(9.41 \, \text{kN}\)
---
**Analysis:**
To solve this problem, you need to calculate the force exerted by the atmospheric pressure on an area of one square foot. Here’s the step-by-step method to solve it:
1. **Convert square feet to square meters:**
- 1 square foot = 0.092903 square meters.
2. **Calculate the force:**
- Use the formula:
\[
\text{Force} = \text{Pressure} \times \text{Area}
\]
- Substitute the given pressure and converted area into the formula:
\[
\text{Force} = 101300 \, \text{Pa} \times 0.092903 \, \text{m}^2
\]
3. **Solve for the force:**
- Calculate the result to find the correct option.
Understanding how to calculate pressure and area conversions is crucial for solving such problems in physics. Use these steps to find the force exerted by the atmosphere on any given area.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fab8e90de-1834-4897-8d02-45bfaff51002%2F61d07909-4485-4f99-a848-472b9a093037%2F9uyr07d_processed.png&w=3840&q=75)
Transcribed Image Text:**Question:**
Atmospheric pressure at sea level is \(101.3 \times 10^3 \, \text{Pa}\). What is the force exerted by the atmosphere on a square foot of area?
**Options:**
- \(101 \, \text{kN}\)
- \(109 \, \text{kN}\)
- \(332 \, \text{kN}\)
- \(30.9 \, \text{kN}\)
- \(9.41 \, \text{kN}\)
---
**Analysis:**
To solve this problem, you need to calculate the force exerted by the atmospheric pressure on an area of one square foot. Here’s the step-by-step method to solve it:
1. **Convert square feet to square meters:**
- 1 square foot = 0.092903 square meters.
2. **Calculate the force:**
- Use the formula:
\[
\text{Force} = \text{Pressure} \times \text{Area}
\]
- Substitute the given pressure and converted area into the formula:
\[
\text{Force} = 101300 \, \text{Pa} \times 0.092903 \, \text{m}^2
\]
3. **Solve for the force:**
- Calculate the result to find the correct option.
Understanding how to calculate pressure and area conversions is crucial for solving such problems in physics. Use these steps to find the force exerted by the atmosphere on any given area.
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