a typic omework during their last year in high school. Probabilities for the outcomes are Less than one hour 0.1 Time Probability 1 to 5 hours 6 to 10 hours 0.5 0.2 week hey spent studying or doin More than 10 hours ? What must be the probability that a randomly chosen first-year college student says they spent more than 10 hours per wee udying or doing homework during their last year in high school? Use decimal notation. Give your answer as an exact number.)

College Algebra
10th Edition
ISBN:9781337282291
Author:Ron Larson
Publisher:Ron Larson
Chapter8: Sequences, Series,and Probability
Section8.7: Probability
Problem 4ECP: Show that the probability of drawing a club at random from a standard deck of 52 playing cards is...
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To calculate the probability that a randomly chosen first-year college student spent more than 10 hours per week studying or doing homework during their last year in high school, we need to consider the given probabilities for the other time intervals. The table provides the following probabilities:

- Less than one hour: 0.1
- 1 to 5 hours: 0.5
- 6 to 10 hours: 0.2
- More than 10 hours: ?

Since the sum of all probabilities must equal 1, we can set up the equation:

\[ 
0.1 + 0.5 + 0.2 + \text{(Probability of more than 10 hours)} = 1 
\]

Calculating the unknown probability:

\[ 
0.8 + \text{(Probability of more than 10 hours)} = 1 
\]

\[ 
\text{Probability of more than 10 hours} = 1 - 0.8 = 0.2 
\]

Therefore, the probability that a student spent more than 10 hours per week studying or doing homework is 0.2. 

**Probability:** 0.2
Transcribed Image Text:To calculate the probability that a randomly chosen first-year college student spent more than 10 hours per week studying or doing homework during their last year in high school, we need to consider the given probabilities for the other time intervals. The table provides the following probabilities: - Less than one hour: 0.1 - 1 to 5 hours: 0.5 - 6 to 10 hours: 0.2 - More than 10 hours: ? Since the sum of all probabilities must equal 1, we can set up the equation: \[ 0.1 + 0.5 + 0.2 + \text{(Probability of more than 10 hours)} = 1 \] Calculating the unknown probability: \[ 0.8 + \text{(Probability of more than 10 hours)} = 1 \] \[ \text{Probability of more than 10 hours} = 1 - 0.8 = 0.2 \] Therefore, the probability that a student spent more than 10 hours per week studying or doing homework is 0.2. **Probability:** 0.2
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