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A two-word instruction is stored in memory at an address designated by the symbol A. The address field of the instruction (stored at A + 1) is designated by the symbol Y. The operand used during the execution of the instruction is stored at an address symbolized by EA. An index register contains the value X. With the help of diagram, state how EA is calculated from the other addresses if the addressing mode of the instruction is (1)- direct (2)- indirect (3)- indexed (4)-Relative (5)- Register indirect

A two-word instruction is stored in memory at an address designated by the symbol A. The address field of the instruction (stored at A + 1) is designated by the symbol Y. The operand used during the execution of the instruction is stored at an address symbolized by EA. An index register contains the value X. With the help of diagram, state how EA is calculated from the other addresses if the addressing mode of the instruction is (1)- direct (2)- indirect (3)- indexed (4)-Relative (5)- Register indirect

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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A two-word instruction is stored in memory at an address designated by the symbol A. The address field of the instruction (stored at A + 1) is designated by the symbol Y. The operand used during the execution of the instruction is stored at an address symbolized by EA. An index register contains the value X. With the help of diagram, state how EA is calculated from the other addresses if the addressing mode of the instruction is

(1)- direct

(2)- indirect

(3)- indexed

(4)-Relative

(5)- Register indirect

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