a) Two narrow slits 80 μm apart are illuminated with light of wavelength 620 nm. What is the angle of the first fringe in radians? In degrees?
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A: Given that Wavelength of incident light λ = 660 nm Angular position of first dark fringe θ1 = 4.2…
Q: A thin film of thickness 1.5 µm is placed in Michelson interferometer which causes a 7.5 fringe…
A: Thickness, t = 1.5 μm Shifts, ∆y1 = 7.5 fringes ∆y2 = 9 fringes Thickness of second film, t2 = ?
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A: Given:- The wavelength of the light is λ=565 nm= 565 x 10-6mm. The first dark fringe of the…
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A: Wavelength of incidence light = 615 nm = 615 x 10-9 m Slit width, d=0.25 mm = 0.25 x 10-3 m…
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A: Condition for dark fringes
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A: Solution: Given: λ = wavelength of light used = 444 nm = 444 x 10-9 m θ = angle corresponding to…
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A: Wavelength of light: λ = 693 nm = 6.93 × 10-7 m Seperation between slits: d = 4.43 × 10-6 m We know…
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Q: Light of wavelength 564 nm passes through a slit 5.10 x 106 m wide and falls on a screen that is…
A: Solution:Given:1 nm = 10-9 ma = width of single slit = 5.10 x 10-6 mm = order of minima = 3λ =…
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A: Here, mλ=d sinθmθm=sin-1mλd
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A: Since you have pasted multiple question and asked to solve only question 7 so we will solve only…
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Q: b) For what wavelength of light the first-order dark fringe (i.e., m= 0) be observed at the same…
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A: Given data: Wavelength of the light, λ=495 nm=495×10-9 m Order of bright fringe, n=2 Bragg angle,…
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Q: A grating is labelled "500 lines per mm". Calculate the position of the first-order maxima when red…
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Q: A 0.72 mm diameter hole is illuminated by infrared light of wavelength 2.5 μm. What is the angle of…
A: Given, Diameter = 0.72 mm Wavelength = 2.5 micrometers We need to find, Angle of the dark fringe =?
Q: A thin film of thickness 1.5 µm is placed in Michelson interferometer which causes a 7.5 fringe…
A:
Q: A light with wavelength λ = 580 nm falls on a pair of closely separated slits. The first dark fringe…
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Q: A double-slit experiment is carried out with slit spacing d = 0.41 mm. The screen is at a distance…
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Q: Visible light is incident perpendicular to a grating with 430 rulings/mm. What is the longest…
A: We know that, Diffraction formula- d.Sinθ= mλwhen , Sinθ= 1 then wavelength will be…
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Q: Using the result of the problem above, calculate thedistance between fringes for 633-nm light…
A: The distance between the fringes is given by the equation
Q: Due to the wave nature of light shines on a single slit will produce a diffraction pattern. Green…
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Q: A single slit is illuminated with 610-nm light, and the resulting diffraction pattern is viewed on a…
A: Wavelength ( λ) = 610 nm Screen distance ( L ) = 2.3 m Distance between the first and second dark…
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