A tutor promises to improve GMAT scores of students by more than 42 points after three lessons. To see if this is true, the tutor takes a sample of 49 students' test scores after and before they received tutoring. The mean difference was 45 points better after tutoring, with a standard deviation of the differences equal to 14 points. Let µp denote the mean of the difference: score after tutoring minus score before tutoring. Which of the following is the correct value of the test statistic? Multiple Choice t48 = 1.5000 2 = 1.4643 t48 = 1.4643 z = 1.5000

A tutor promises to improve GMAT scores of students by more than 42 points after three lessons. To see if this is true, the tutor takes a sample of 49 students' test scores after and before they received tutoring. The mean difference was 45 points better after tutoring, with a standard deviation of the differences equal to 14 points. Let µp denote the mean of the difference: score after tutoring minus score before tutoring. Which of the following is the correct value of the test statistic? Multiple Choice t48 = 1.5000 2 = 1.4643 t48 = 1.4643 z = 1.5000

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.

Question

A tutor promises to improve GMAT scores of students by more than 42 points after three lessons. To see if this is true, the tutor takes a sample of 49
students' test scores after and before they received tutoring. The mean difference was 45 points better after tutoring, with a standard deviation of the
differences equal to 14 points. Let up denote the mean of the difference: score after tutoring minus score before tutoring. Which of the following is the
correct value of the test statistic?
Multiple Choice
t48 = 1.5000
z = 1.4643
t48 = 1.4643
z = 1.5000

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