A tugboat with a mass of mtug pushes a barge with a mass of mþarge SO that, starting from rest, they reach a final speed vf. Assume that gravity and the water's buoyancy cancel each other, and that we need to consider only interactions through the tug's propeller and front bumper. (a) By how much does the tugboat's momentum change? (b) How much impulse did the tugboat transfer to the barge (through the bumper)? (c) How much impulse, therefore, did the tugboat receive from the barge (through the bumper)? (d) How much impulse did the propeller transfer to the tugboat? (e) Evaluate your result from part (d) for mtug [Aptug] m/s. = 2.0 × 10° kg, mbarge = 8.0 x 10° kg and vf = 2.0 2.5 m/s you should find Check: For Mtug 2.3 x 106 kg m/s. = 2.2 x 10° kg, mþarge = 7.0 × 105 kg and Vf %3D prop

icon
Related questions
Question
1.2 A tugboat with a mass of mtug pushes a barge with a mass of mbarge So that, starting from rest, they
reach a final speed vf. Assume that gravity and the water's buoyancy cancel each other, and that we
need to consider only interactions through the tug's propeller and front bumper.
(a) By how much does the tugboat's momentum change?
(b) How much impulse did the tugboat transfer to the barge (through the bumper)?
(c) How much impulse, therefore, did the tugboat receive from the barge (through the bumper)?
(d) How much impulse did the propeller transfer to the tugboat?
(e) Evaluate your result from part (d) for mtug = 2.0 × 10° kg, mparge
m/s.
tug
= 8.0 x 10° kg and vf = 2.0
= 2.2 x 105 kg, mbarge = 7.0 x 105 kg and vf = 2.5 m/s you should find
Check: For Mtug
[Ape prop
= 2.3 x 106 kg m/s.
Transcribed Image Text:1.2 A tugboat with a mass of mtug pushes a barge with a mass of mbarge So that, starting from rest, they reach a final speed vf. Assume that gravity and the water's buoyancy cancel each other, and that we need to consider only interactions through the tug's propeller and front bumper. (a) By how much does the tugboat's momentum change? (b) How much impulse did the tugboat transfer to the barge (through the bumper)? (c) How much impulse, therefore, did the tugboat receive from the barge (through the bumper)? (d) How much impulse did the propeller transfer to the tugboat? (e) Evaluate your result from part (d) for mtug = 2.0 × 10° kg, mparge m/s. tug = 8.0 x 10° kg and vf = 2.0 = 2.2 x 105 kg, mbarge = 7.0 x 105 kg and vf = 2.5 m/s you should find Check: For Mtug [Ape prop = 2.3 x 106 kg m/s.
Expert Solution
Step 1

Given: 

mass of tug = mtug=2.2 ×105 kgmass of barge = mbarge = 7×105 kgFinal velocity = vf = 2.5 m/sInitial velocity = 0 m/s

trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps

Blurred answer