A trunnion of diameter 12.363" has to be cooled from a room temperature of 80°F before it is shrink fitted into a steel hub (Figure 1). Figure 1 Trunnion to be slid through the hub after contracting. The equation that gives the diametric contraction AD of the trunnion in a dry-ice/alcohol mixture (boiling temperature is -108°F) is given by -108 AD=12.363 [α (T) dT 80 The equation for the thermal expansion coefficient, α = a₁ + a₂T+ a¸², is obtained using regression analysis where the constants of the model are found by solving the following simultaneous linear equations. 24 -2860 -2860 7.26×105 7.26×105 a₁ -1.86472×108 a₂ 1.057 × 10-4 =-1.04162×10-2 7.26x105 -1.86472×108 5.24357x10¹º a₂ 2.56799 Find the values of a₁, a₂, and a3 using naïve Gauss elimination.

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A trunnion of diameter 12.363" has to be cooled from a room temperature of 80°F before it
is shrink fitted into a steel hub (Figure 1).
Figure 1 Trunnion to be slid through the hub after contracting.
The equation that gives the diametric contraction AD of the trunnion in a dry-ice/alcohol
mixture (boiling temperature is -108°F) is given by
-108
AD=12.363 [α (T) dT
80
The equation for the thermal expansion coefficient, α = a₁ + a₂T+ a¸², is obtained using
regression analysis where the constants of the model are found by solving the following
simultaneous linear equations.
24
-2860
-2860
7.26×105
7.26×105 a₁
-1.86472×108 a₂
1.057 × 10-4
=-1.04162×10-2
7.26x105 -1.86472×108
5.24357x10¹º a₂
2.56799
Find the values of a₁, a₂, and a3 using naïve Gauss elimination.
Transcribed Image Text:A trunnion of diameter 12.363" has to be cooled from a room temperature of 80°F before it is shrink fitted into a steel hub (Figure 1). Figure 1 Trunnion to be slid through the hub after contracting. The equation that gives the diametric contraction AD of the trunnion in a dry-ice/alcohol mixture (boiling temperature is -108°F) is given by -108 AD=12.363 [α (T) dT 80 The equation for the thermal expansion coefficient, α = a₁ + a₂T+ a¸², is obtained using regression analysis where the constants of the model are found by solving the following simultaneous linear equations. 24 -2860 -2860 7.26×105 7.26×105 a₁ -1.86472×108 a₂ 1.057 × 10-4 =-1.04162×10-2 7.26x105 -1.86472×108 5.24357x10¹º a₂ 2.56799 Find the values of a₁, a₂, and a3 using naïve Gauss elimination.
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