A truck travels 10.5 km in direction 37.9° north of west. What is the x-component of its displacement in meters. Consider the east direction fo be the positive x-direction and north to be the positive y-direction.
A truck travels 10.5 km in direction 37.9° north of west. What is the x-component of its displacement in meters. Consider the east direction fo be the positive x-direction and north to be the positive y-direction.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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
Transcribed Image Text:**Problem Statement:**
A truck travels 10.5 km in a direction 37.9° north of west. What is the x-component of its displacement in meters? Consider the east direction to be the positive x-direction and north to be the positive y-direction.
Round your answer to 0 decimal places.
**Solution Explanation:**
1. **Understanding Directions:**
- The truck's travel direction is 37.9° north of west.
- This means we need to analyze the movement in a coordinate system where:
- East is the positive x-direction.
- North is the positive y-direction.
2. **Displacement Components:**
- The total distance traveled by the truck is 10.5 km.
- We need to find the x-component (west-east direction) of this displacement.
3. **Using Trigonometry:**
- To determine the x-component, we use the cosine function.
- x-component = Total Distance * cos(angle)
- Here, the angle is referenced from west (+180°), so we'll use angle = 180° - 37.9° = 142.1°
4. **Calculating the X-Component:**
- Convert 10.5 km to meters: \(10.5 \text{ km} \times 1000 \text{ m/km} = 10500 \text{ m}\)
- x-component = \( 10500 \text{ m} \times \cos(142.1°) \)
5. **Computing the Value:**
- Using a calculator:
\( \cos(142.1°) \approx -0.7547\)
- x-component = \( 10500 \times -0.7547 \approx -7924.35 \text{ m} \)
6. **Rounding the Answer:**
- Rounded answer to 0 decimal places: -7924 m
**Answer:**
The x-component of the truck's displacement is -7924 meters.
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