A triangular duct whose surfaces are all black has a length of L=0.75 m. By considering the details given below, calculate the total heat transfer rate by radiation from the bottom surface (Surface-1) to the other surfaces (Surface-2 and Surface-3) of the duct, in W. o=5.67x108 W/(m²K4) L1=1.04 m, T1=617 K L2=0.64 m, T2=440 K L3=0.84 m, T3=350 K
A triangular duct whose surfaces are all black has a length of L=0.75 m. By considering the details given below, calculate the total heat transfer rate by radiation from the bottom surface (Surface-1) to the other surfaces (Surface-2 and Surface-3) of the duct, in W. o=5.67x108 W/(m²K4) L1=1.04 m, T1=617 K L2=0.64 m, T2=440 K L3=0.84 m, T3=350 K
Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)
8th Edition
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Author:Kreith, Frank; Manglik, Raj M.
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Chapter8: Natural Convection
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Problem 8.15P: 8.15 A mercury bath at is to be heated by immersing cylindrical electric heating rods, each 20 cm...
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heat transfer
![A triangular duct whose surfaces are all black has a length of L=0.75 m. By considering the details
given below, calculate the total heat transfer rate by radiation from the bottom surface (Surface-1) to
the other surfaces (Surface-2 and Surface-3) of the duct, in W.
o=5.67x10-8 W/(m²Kª)
L1=1.04 m, T1=617 K
L2=0.64 m, T2=440 K
L3=0.84 m, T3=350 K
L2
L3
(1)
L1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc684b886-2715-4503-ae8d-787b942b8b7a%2F0398c773-bf98-4d45-8062-2ea5781a1655%2F429qm2y_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A triangular duct whose surfaces are all black has a length of L=0.75 m. By considering the details
given below, calculate the total heat transfer rate by radiation from the bottom surface (Surface-1) to
the other surfaces (Surface-2 and Surface-3) of the duct, in W.
o=5.67x10-8 W/(m²Kª)
L1=1.04 m, T1=617 K
L2=0.64 m, T2=440 K
L3=0.84 m, T3=350 K
L2
L3
(1)
L1
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