A triangular duct whose surfaces are all black has a length of L=0.75 m. By considering the details given below, calculate the total heat transfer rate by radiation from the bottom surface (Surface-1) to the other surfaces (Surface-2 and Surface-3) of the duct, in W. o=5.67x108 W/(m²K4) L1=1.04 m, T1=617 K L2=0.64 m, T2=440 K L3=0.84 m, T3=350 K

A triangular duct whose surfaces are all black has a length of L=0.75 m. By considering the details given below, calculate the total heat transfer rate by radiation from the bottom surface (Surface-1) to the other surfaces (Surface-2 and Surface-3) of the duct, in W. o=5.67x108 W/(m²K4) L1=1.04 m, T1=617 K L2=0.64 m, T2=440 K L3=0.84 m, T3=350 K

Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)

8th Edition

ISBN:9781305387102

Author:Kreith, Frank; Manglik, Raj M.

Publisher:Kreith, Frank; Manglik, Raj M.

Chapter8: Natural Convection

Section: Chapter Questions

Problem 8.15P: 8.15 A mercury bath at is to be heated by immersing cylindrical electric heating rods, each 20 cm...

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SOLVE SIMPLY SO I CAN UNDERSTAND :)FINAL ANSWERS MUST BE ROUND TO 4 DECIMAL PLACES AND BOXED!
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