A triangle is defined by the three points: A = (8, 8) В 3 (10,4) C = (1, 2). Determine all three angles in the triangle (in radians) Os = %3D Oc = II

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter8: Applications Of Trigonometry
Section8.3: Vectors
Problem 11E
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I do not know how to solve this I do not understand the example

 

I know the last one is 0.49 not sure about the first two

Solution:
Solution:
АВ
(a) First we find the two vectors
(7, 2) and AĆ
(8, 1).
Then, from the identity v. w = ||v||||w|| cos 0 we solve for 0 which yields
0 = cos
(T).
Therefore, 0a
(7,2)·(8,1)
= COS
I|(7,2)|||(8,1)|| ) = 0.153945.
(b) We follow the identical procedure as in part a, with the two vectors BA = (-7, – 2)
and BC = (1, –1).
-1
<-7,-2)-(1,–1)
- 2.07789.
= COS
(-7,–2)|||(1,–1)|)
(c) We follow the identical procedure as in parts a and b, with the two vectors
CA
(-8, –1) and CB = (-1,1).
(-8,–1)·(-1,1)
-8,–1)|||(-1,1)|| )
-1
Oc= cos
:0.909753.
Transcribed Image Text:Solution: Solution: АВ (a) First we find the two vectors (7, 2) and AĆ (8, 1). Then, from the identity v. w = ||v||||w|| cos 0 we solve for 0 which yields 0 = cos (T). Therefore, 0a (7,2)·(8,1) = COS I|(7,2)|||(8,1)|| ) = 0.153945. (b) We follow the identical procedure as in part a, with the two vectors BA = (-7, – 2) and BC = (1, –1). -1 <-7,-2)-(1,–1) - 2.07789. = COS (-7,–2)|||(1,–1)|) (c) We follow the identical procedure as in parts a and b, with the two vectors CA (-8, –1) and CB = (-1,1). (-8,–1)·(-1,1) -8,–1)|||(-1,1)|| ) -1 Oc= cos :0.909753.
A triangle is defined by the three points:
A = (8,8)
В %3 (10,4)
С 3 (1,2).
Determine all three angles in the triangle (in radians).
Oa =
Ob =
Oc =
Transcribed Image Text:A triangle is defined by the three points: A = (8,8) В %3 (10,4) С 3 (1,2). Determine all three angles in the triangle (in radians). Oa = Ob = Oc =
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