A trapezoidal is shown below. The particulars of the channel are as such: • Side slopes are 1 in 0.5 m. • Manning's n = 0.015 • Slope of channel is 1 m in 1 km 0.5 a. Using a value of 5 m for the bottom width and a normal depth of flow of 2 m, determi the following: i. Discharge ii. iii. b Mean Velocity Reynolds No.
A trapezoidal is shown below. The particulars of the channel are as such: • Side slopes are 1 in 0.5 m. • Manning's n = 0.015 • Slope of channel is 1 m in 1 km 0.5 a. Using a value of 5 m for the bottom width and a normal depth of flow of 2 m, determi the following: i. Discharge ii. iii. b Mean Velocity Reynolds No.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![A trapezoidal is shown below. The particulars of the channel are as such:
• Side slopes are 1 in 0.5 m.
Manning's n = 0.015
• Slope of channel is 1 m in 1 km
0.5
b
a. Using a value of 5 m for the bottom width and a normal depth of flow of 2 m, determin
the following:
i.
ii.
iii.
Discharge
Mean Velocity
Reynolds No.
b. If the discharge were 35 m³/s and bottom width was 5m, what would the normal depth
of flow be? All other conditions remain the same.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa4b9ff9a-402a-48aa-9826-14de82cac04c%2Ff0140d4c-9663-4b47-b1a1-4883517a11e4%2Fnjo60zm_processed.png&w=3840&q=75)
Transcribed Image Text:A trapezoidal is shown below. The particulars of the channel are as such:
• Side slopes are 1 in 0.5 m.
Manning's n = 0.015
• Slope of channel is 1 m in 1 km
0.5
b
a. Using a value of 5 m for the bottom width and a normal depth of flow of 2 m, determin
the following:
i.
ii.
iii.
Discharge
Mean Velocity
Reynolds No.
b. If the discharge were 35 m³/s and bottom width was 5m, what would the normal depth
of flow be? All other conditions remain the same.
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