A trapezoidal channel is 5.0 km long with the side slopes of Z=0.5 constructed in clay soil. Up to the first 2 km, the bed-width of the channel is 4.90 m and the depth of flow is 1.05 m. Thereafter, the bed-width and the depth are 4.0 m and 0.885 m, respectively, right up to the downstream end of the channel. Estimate the total seepage loss through the channel by Moles-Worth equation.
A trapezoidal channel is 5.0 km long with the side slopes of Z=0.5 constructed in clay soil. Up to the first 2 km, the bed-width of the channel is 4.90 m and the depth of flow is 1.05 m. Thereafter, the bed-width and the depth are 4.0 m and 0.885 m, respectively, right up to the downstream end of the channel. Estimate the total seepage loss through the channel by Moles-Worth equation.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![Exercise [5]
A trapezoidal channel is 5.0 km long with the side slopes of Z-0.5
constructed in clay soil. Up to the first 2 km, the bed-width of the channel
is 4.90 m and the depth of flow is 1.05 m. Thereafter, the bed-width and
the depth are 4.0 m and 0.885 m, respectively, right up to the downstream
end of the channel. Estimate the total seepage loss through the channel by
Moles-Worth equation.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F25874860-8d2f-4970-be75-cd18b44649c1%2F43c0c74f-a6a5-41eb-8755-8ade43929a48%2Fdhyeg7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Exercise [5]
A trapezoidal channel is 5.0 km long with the side slopes of Z-0.5
constructed in clay soil. Up to the first 2 km, the bed-width of the channel
is 4.90 m and the depth of flow is 1.05 m. Thereafter, the bed-width and
the depth are 4.0 m and 0.885 m, respectively, right up to the downstream
end of the channel. Estimate the total seepage loss through the channel by
Moles-Worth equation.
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