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A transmitter uses a carrier frequency of 1100 Hz so that the unmodulated carrier is A, cos(2nf t). Determine both the phase and frequency deviation in HZ for the following transmitter output: x, (t) = cos[27(1300)t] Select one: do O a o()=-2(1100)t+2(1300)t, and -(-)-1100 + 3900t2 27 dt O b.o(t)=-21(1000)t+27(1200)t?, and ()=-1000 + 3600t2 do 27 dt O COU=-2r(1100)t-27(1300)t, and )=-1100 + 3900t do O d. o(t)=2m(1100)t-2r(1300)t, and ()=1100 - 3900t2 1 do 27 dt

A transmitter uses a carrier frequency of 1100 Hz so that the unmodulated carrier is A, cos(2nf t). Determine both the phase and frequency deviation in HZ for the following transmitter output: x, (t) = cos[27(1300)t] Select one: do O a o()=-2(1100)t+2(1300)t, and -(-)-1100 + 3900t2 27 dt O b.o(t)=-21(1000)t+27(1200)t?, and ()=-1000 + 3600t2 do 27 dt O COU=-2r(1100)t-27(1300)t, and )=-1100 + 3900t do O d. o(t)=2m(1100)t-2r(1300)t, and ()=1100 - 3900t2 1 do 27 dt

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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O e. 34 A transmitter uses a carrier frequency of 1100 Hz so that the unmodulated carrier is A cos(2nf t)- Determine both the phase and frequency deviation in HZ for the following transmitter output: x, (t) = cos[2#(1300)t] Select one: do O a o()=-2(110o)t+2(1300)t, and G)-1100 + 3900t2 dt do O b.o(()= 2r(1000)t-27(1200)t?, and )=-1000 + 3600t2 27 OCO0--27(110ot-27(1300)t, and -G)=1100 + 3900t do O d. o(D=2m(1100)1-27(1 300)1, and )-1100 - 3900t2 do lon 31 A superheterodyne receiver operates n the freguency range of 58 MH2-68 MHZ The intermediate frec local oscillater frequency fro ere chosen such that yet TE ho tisrequired thacthe Image frequend
Transcribed Image Text:O e. 34 A transmitter uses a carrier frequency of 1100 Hz so that the unmodulated carrier is A cos(2nf t)- Determine both the phase and frequency deviation in HZ for the following transmitter output: x, (t) = cos[2#(1300)t] Select one: do O a o()=-2(110o)t+2(1300)t, and G)-1100 + 3900t2 dt do O b.o(()= 2r(1000)t-27(1200)t?, and )=-1000 + 3600t2 27 OCO0--27(110ot-27(1300)t, and -G)=1100 + 3900t do O d. o(D=2m(1100)1-27(1 300)1, and )-1100 - 3900t2 do lon 31 A superheterodyne receiver operates n the freguency range of 58 MH2-68 MHZ The intermediate frec local oscillater frequency fro ere chosen such that yet TE ho tisrequired thacthe Image frequend
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