A toy store would like to open a new store in the city of Thousand Oaks, and they would like to know what proportion of households have kids. Out of 600 households sampled, 148 had kids. Based on this, construct a 99% confidence interval for the true population proportion of Thousand Oaks households with kids. Enter your answer as an open-interval (i.e., parentheses) using decimals (not percents) accurate to three decimal places. Confidence interval =    Express the same answer as a tri-linear inequality using decimals (not percents) accurate to three decimal places. < p <    Express the same answer using the point estimate and margin of error. Give your answers as decimals, to three places.p =  _____±___

Q: In a survey of 3001 ​adults, 1486 say they have started paying bills online in the last year.…

A: Assuming that the number of people paying bills online has a binomial distribution with n=3001, and…

Q: In a survey of 2865 ​adults, 1413 say they have started paying bills online in the last year.…

A:

Q: A poll reported that only 507 out of a total of 1809 adults in a particular region said they had a​…

A: The sampled no. of adults, i.e., the sample size, n=1809. The no. of sampled adults who expressed a…

Q: n a survey of 2558 ​adults, 1413 say they have started paying bills online in the last year.…

A: Solution: Given information: n= 2558 Sample size of adults  x = 1413 adults started paying bills…

Q: A survey of 700 non-fatal accidents showed that 167 involved uninsured drivers. Construct a 99%…

A: Given data,n=700x=167Point estimate isp=xn=167700=0.2386Construct a 99% confidence interval?

Q: In a survey of 3254 ​adults, 1433 say they have started paying bills online in the last year.…

A: Given X=1433 n=3254

Q: In a survey of 2703 ​adults, 1438 say they have started paying bills online in the last year.…

A: We have given that, Number of favorable cases(X) = 1438,   Sample size(n) = 2703 Sample proportion…

Q: Out of 400 people sampled, 32 had kids. Based on this, construct a 95% confidence interval for the…

A: Solution: Let X be the number of people had kids and n be the sample number of people. From the…

Q: Suppose we take a survey of 200 students and ask how much they study per week. The result is an…

A: From the above data  We are given that the  95% confidence interval is (10, 10.5). The population…

Q: We wish to estimate what percent of adult residents in Ventura County like chocolate. Out of 500…

A: The sample proportion of the sample of size n can be defined as:  Here, X = Total number of success…

Q: a survey of 3447 adults, 1477 say they have started paying bills online in the last year.…

A:

Q: Insurance companies are interested in knowing the population percent of drivers who always buckle up…

A:

Q: A new fertilizer was applied to the soil of 276 bean plants. 24% showed increased growth. Find the…

A: Given Data: p=0.24 n=276   z-value corresponding to 95% Confidence level=1.96

Q: A sample of 500 nursing applicants included 80 men.  Determine the 95% confidence interval for the…

A:

Q: In a study of 120 randomly selected families, 50 said they streamed their television content. Find…

A:

Q: e confidence interval for a population mean is (240.53, 240.79). What are the sample mean and the…

A: The confidence interval for a population mean is (240.53, 240.79)WE HAVE TO FIND OUT THE MEAN AND…

Q: What is the upper bound of the confidence interval? A 98% confidence interval for the data: 25, 38,…

A: We have given data, X 25 38 62 45 61 38 21 42 31 35 The confidence level is 1-α=0.98.

Q: magine that you conduct a study and estimate that the prevalence of hypertension among employees of…

A: It is given that the estimated prevalence is 24%.

Q: In a survey of 2552 ​adults, 1423 say they have started paying bills online in the last year.…

A: Given that, In a survey of 2552 adults, 1423 say they have started paying bills online in the last…

Q: In a survey of 3260​ adults, 1456 say they have started paying bills online in the last year.…

A: Givenn=3260x=1456p^=xn=14563260=0.4466

Q: If n=540 and (p-hat) = 0.13, construct a 99% confidence interval. Give your answers to three…

A: We have given that,  Sample size (n) = 540  Sample proportion (p-hat) = 0.13 Then,  We will find the…

Q: business conducts a random sample of 89 of its customers and find that 44 of them think the company…

A:

Q: To construct a confidence interval, we have to make three assumptions. explain what are those…

A:

Q: The 95​% confidence interval for the proportion that express a great deal of confidence or quite a…

A: A poll reported that only 645 out of a total of 2029 adults in a particular region said they had a​…

Q: If n=240 and X = 192, construct a 90% confidence interval. Enter your answer as an open-interval…

A: 1. The given values are n=240,x=192. The proportion of x is, p^=xn=192240=0.8 Computation of…

Q: What does Level of Confidence indicates?

A:

Q: Construct a​ 99% confidence interval for the population proportion. Interpret the results.

A:

Q: In a survey of 2782 adults, 1411 say they have started paying bills online in the last year.…

A:

Q: A motorcycle dealer with the "Hd" brand wants to know the percentage of students in the city "X" who…

A: We have to find confidence interval.

Q: In general, when you increase the confidence level for a confidence interval using the same sample…

A: As confidence level increases critical value is going to increase .  Here they given sample…

Q: A firm randomly samples 100 workers at its New York plant and finds that 32% of the workers say that…

A: The proportion of workers who say that they buy the firm’s product is 0.32.

Q: For a confidence level of 99% with a sample size of 22, find the t-score. Did not see how to work…

A: The provided information is:

Q: In a survey of 2646 ​adults, 1401 say they have started paying bills online in the last year.…

A: Number of adults (n)  = 2646 Number of adults who say they have started paying bills online in the…

Q: Which of the following would likely show a bimodal distribution in a histogram? The number of hours…

A:

Q: Suppose we take a survey of 400 students and ask how much they study per week. The result is an…

A: The 100 (1 – α)% confidence interval provides an interval estimation of the required population…

Q: n a survey of 3196 adults, 1405 say they have started paying bills online in the last year.…

A: Given data, n=3196 x=1405 p=x/n=1405/3196 =0.4396 z-value at 99% confidence is Zc=2.576

Q: In a survey of 2588 ​adults, 1466 say they have started paying bills online in the last year.…

A: Construct 99% confidence interval for population proportion:The sample of 2,588 adults among that…

Q: A poll showed that 385 out of 700 adults said they would be interested in traveling to outer space…

A: This question requires accurate results, Hence I will use excel to solve this question.…

Q: An actuary is interested in estimating the proportion of young adults who plan to have children…

A: We need to construct the 99% confidence interval for the population proportion. We have been…

Q: In a survey of 3246 ​adults, 1418 say they have started paying bills online in the last year.…

A: Given information Number of adults surveyed(n) = 3246 Number of people who started paying bills…

Q: A survey was done of 55 Lake Tahoe residents to see how many times they went to a Lake Tahoe beach…

A: In this scenario, the 95% confidence interval for the mean was found to be (3.1, 7.2).  The…

Q: The ability to find a job after graduation is very important to GSU students as it is students at…

A: Sample size n=3878Favorable cases x=3241

Q: An online poll of 810 adults found that 53% of the respondents think critical thinking should be…

A: Given info: An online poll of 810 adults found that 53% of the respondents think critical thinking…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.