A toy rocket of mass 0.50kg starts from rest on the ground and is launched upward, experiencing a vertical net force. The rocket’s upward acceleration a for the first 6 seconds is given by the equation a=K−Lt2, where K=9.0m/s2, L=0.25m/s4, and t is the time in seconds. At t=6.0s, the fuel is exhausted and the rocket is under the influence of gravity alone. Assume air resistance and the rocket’s change in mass are negligible. (d) Calculate the maximum height reached by the rocket relative to its launching point.
A toy rocket of mass 0.50kg starts from rest on the ground and is launched upward, experiencing a vertical net force. The rocket’s upward acceleration a for the first 6 seconds is given by the equation a=K−Lt2, where K=9.0m/s2, L=0.25m/s4, and t is the time in seconds. At t=6.0s, the fuel is exhausted and the rocket is under the influence of gravity alone. Assume air resistance and the rocket’s change in mass are negligible.
(d) Calculate the maximum height reached by the rocket relative to its launching point.
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in the second photo, when you plugged 6 in for t, shouldn't it be a = (9) - (0.25)(6)2? like since you're substituting it into the accel equation that you had in the first photo? but i don't know if that would work because then the accel would be 0
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