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- In the 1992 presidential election, Alaska's 40 election districts averaged 1824 votes per district for President Clinton. The standard deviation was 573. (There are only 40 election districts in Alaska.) The distribution of the votes per district for President Clinton was bell-shaped. Let X = number of votes for President Clinton for an election district. (Source: The World Almanac and Book of Facts) Round all answers except part e. to 4 decimal places.a. What is the distribution of X? X ~ N(,)b. Is 1824 a population mean or a sample mean? c. Find the probability that a randomly selected district had fewer than 1872 votes for President Clinton. d. Find the probability that a randomly selected district had between 1842 and 2091 votes for President Clinton. e. Find the first quartile for votes for President Clinton. Round your answer to the nearest whole number.The scoring averages (points per game) of the starting lineup of a basketball team are as follows: 6.2, 11.4, 18.3, 22.9 and 14.8. What is the standard deviation of their averages? a. 7.14 b. 6.39 c. 5.72 d 5.22Assume a mean of 105 papers and a standard deviation of 15 papers. Pays 40¢ for each paper, paper sells for 90¢, how many papers should the newsperson carry. 108 109 105 110
- A student receives the following yudes, with an A worth 4 points, a B worth 3 points, a C worth 2 points, and a D worth 1 point. What is the student's weighted mean nts grade point score? B in 3 four-credit classes D in 1 three-credit class C in 1 two-credit class sour A in 1 three-credit class cess Mean grade point score is (Round to the nearest tenth as needed.) cessIn the 1992 presidential election, Alaska's 40 election districts averaged 1993 votes per district for President Clinton. The standard deviation was 584. (There are only 40 election districts in Alaska.) The distribution of the votes per district for President Clinton was bell-shaped. Let X = number of votes for President Clinton for an election district. (Source: The World Almanac and Book of Facts) Round all answers except part e. to 4 decimal places. a. What is the distribution of X? X ~ N( b. Is 1993 a population mean or a sample mean? Select an answer v C. Find the probability that a randomly selected district had fewer than 2053 votes for President Clinton. d. Find the probability that a randomly selected district had between 2074 and 2208 votes for President Clinton. e. Find the 95th percentile for votes for President Clinton. Round your answer to the nearest whole number.If some data is symmetrical and unimodal, and the mean and standard deviation are 230 and 40 respectively: a)How much of the data lies between 190 and 270 b)How much lies between 150 and 230 c)How much lies between 190 and 310
- In the 1992 presidential election, Alaska's 40 election districts averaged 2038 votes per district for President Clinton. The standard deviation was 576. (There are only 40 election districts in Alaska.) The distribution of the votes per district for President Clinton was bell-shaped. Let X = number of votes for President Clinton for an election district. (Source: The World Almanac and Book of Facts) Round all answers except part e. to 4 decimal places.a. What is the distribution of X? X ~ N(,)b. Is 2038 a population mean or a sample mean? Select an answer Population Mean Sample Mean c. Find the probability that a randomly selected district had fewer than 1842 votes for President Clinton. d. Find the probability that a randomly selected district had between 1997 and 2099 votes for President Clinton. e. Find the first quartile for votes for President Clinton. Round your answer to the nearest whole number.A meteorologist relocated to the city of Windhoek and decided to carry out a research on theamount of rainfall a month recorded in the city in a particular year. His data contained thefollowing: 14 14 10 12 11 13 11 11 11 10 13 8 a. Use the data to calculate the Mean, Mode and Median for the set of rainy days. b. Interpret each central measureAn engineer wishes to determine the width of a particular electronic component. If she knows that the standard deviation is 1.3 mm, how many of these components should she consider to be 90% sure of knowing the mean will be within +0.4 mm? O 18 O 13 29 49
- Given the data, calculate the standard deviation for each: 1) 0.85, 0. 82, 0.83 2)0.10, 0.07, 0.05 3) 1.48, 1.43, 1.49 4) 0.58, 0.51, 0.58 5) 0.37, 0.28, 0.35In the 1992 presidential election, Alaska's 40 election districts averaged 1989 votes per district for President Clinton. The standard deviation was 568. (There are only 40 election districts in Alaska.) The distribution of the votes per district for President Clinton was bell-shaped. Let X = number of votes for President Clinton for an election district. (Source: The World Almanac and Book of Facts) Round all answers except part e. to 4 decimal places. a. What is the distribution of X? X ~ N( __ , __ ) b. Is 1989 a population mean or a sample mean? Select an answer _______. c. Find the probability that a randomly selected district had fewer than 2087 votes for President Clinton. _____ d. Find the probability that a randomly selected district had between 1905 and 2194 votes for President Clinton.______ e. Find the first quartile for votes for President Clinton. Round your answer to the nearest whole number. ______
