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а) Tin) 3D 4T(n-1) — 3Т(n-2) + (n + 6)3". Т(0) 3 0; T(1) 3D 1 b) T(n) =3 T(n/3) + 2n; c) T(n) =2 T(n/2) – T(n/4) + nlogn; d) T(n) =T²(n-1) / T(n-2); T(1) = 0 T(1) = 0; T(2) = 1 T(0) = 1; T(1) = 2

а) Tin) 3D 4T(n-1) — 3Т(n-2) + (n + 6)3". Т(0) 3 0; T(1) 3D 1 b) T(n) =3 T(n/3) + 2n; c) T(n) =2 T(n/2) – T(n/4) + nlogn; d) T(n) =T²(n-1) / T(n-2); T(1) = 0 T(1) = 0; T(2) = 1 T(0) = 1; T(1) = 2

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Using the characteristic equation technique, solve each of the following Recurrence Relations. Make sure to: write the characteristic equation - write the general form of the solution write all the equations necessary for solving the constants in the general solution. HOWEVER, you do not have to solve for the constants. Show the result in © notation a) T(n) = 4T(n-1)– 3T(n-2) + (n + 6)3ª. T(0) = 0 ; T(1) =1 b) T(n) = 3 T(n/3) + 2n; c) T(n) =2 T(n/2) – T(n/4) + nlogn; d) T(n) = T²(n-1) / T(n-2); T(1) = 0 T(1) = 0; T(2) = 1 T(0) = 1; T(1) = 2
Transcribed Image Text:Using the characteristic equation technique, solve each of the following Recurrence Relations. Make sure to: write the characteristic equation - write the general form of the solution write all the equations necessary for solving the constants in the general solution. HOWEVER, you do not have to solve for the constants. Show the result in © notation a) T(n) = 4T(n-1)– 3T(n-2) + (n + 6)3ª. T(0) = 0 ; T(1) =1 b) T(n) = 3 T(n/3) + 2n; c) T(n) =2 T(n/2) – T(n/4) + nlogn; d) T(n) = T²(n-1) / T(n-2); T(1) = 0 T(1) = 0; T(2) = 1 T(0) = 1; T(1) = 2
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