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A time varying Harmonic Electric Field is given E = 20.cos (3×10º t – 10 2) *: The resulting displacement current is given by OAJa = - 60 x 109 Eo sin (3 x 10° t – 10 z) X (A/m²) O B.Ja = - - 60 x 109 Eo sin (3 x 10° t – 10 z)Ž (A/m2) OcJa=-j60 x 109 E0 Cos (3 × 10° t - 10 z) (A/m2) OD.J = -j60 × 10° Eo cos ( 10 z) (A/m2) O E. Ja = 20 Eo cos (3 x 10° t - 10 z) X (A/m2 ) %3D O F. None of the given answers

A time varying Harmonic Electric Field is given E = 20.cos (3×10º t – 10 2) *: The resulting displacement current is given by OAJa = - 60 x 109 Eo sin (3 x 10° t – 10 z) X (A/m²) O B.Ja = - - 60 x 109 Eo sin (3 x 10° t – 10 z)Ž (A/m2) OcJa=-j60 x 109 E0 Cos (3 × 10° t - 10 z) (A/m2) OD.J = -j60 × 10° Eo cos ( 10 z) (A/m2) O E. Ja = 20 Eo cos (3 x 10° t - 10 z) X (A/m2 ) %3D O F. None of the given answers

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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A time varying Harmonic Electric Field is given E = 20.cos (3× 10° t - 10 2) *: The resulting displacement current is given by OAJa = O B.Td = 60 x 109 Eo sin (3 x 10° t - 10 z)X (A/m²) - 60 x 109 Eo sin (3 x 10° t- 10 z) Ž (A/m² ) OCJa = -j60 x 10° Eo cos (3 x 10° t - 10 z) * (A/m2) OD.Ja = -j60 x 10° Eo Cos ( 10 z) (A/m²) OE Ja = 20 Eo Cos (3 x 109 t - 10 z)X (A/m2) O F. None of the given answers
Transcribed Image Text:A time varying Harmonic Electric Field is given E = 20.cos (3× 10° t - 10 2) *: The resulting displacement current is given by OAJa = O B.Td = 60 x 109 Eo sin (3 x 10° t - 10 z)X (A/m²) - 60 x 109 Eo sin (3 x 10° t- 10 z) Ž (A/m² ) OCJa = -j60 x 10° Eo cos (3 x 10° t - 10 z) * (A/m2) OD.Ja = -j60 x 10° Eo Cos ( 10 z) (A/m²) OE Ja = 20 Eo Cos (3 x 109 t - 10 z)X (A/m2) O F. None of the given answers
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