A tiger leaps at an angle of 55° abovethe horizontal to catch a bird. When itleaps, the tiger just barely claws thebird at 5.2 m above the ground.1. What was the tiger's initialvelocity?2. How far in advance should thetiger leap?

Name: A tiger leaps at an angle of 55° abovethe horizontal to catch a bird.
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Description: A tiger leaps at an angle of 55° abovethe horizontal to catch a bird. When itleaps, the tiger just barely claws thebird at 5.2 m above the ground.1. What was the tiger's initialvelocity?2. How far in advance should thetiger leap?

Answered: A tiger leaps at an angle of 55° above…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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A tiger leaps at an angle of 55° above
the horizontal to catch a bird. When it
leaps, the tiger just barely claws the
bird at 5.2 m above the ground.
1. What was the tiger's initial
velocity?
2. How far in advance should the
tiger leap?

Expert Solution

Step 1

(1)

The initial velocity in the vertical direction is $V \sin (55 °)$

The final vertical velocity is zero.

Let's use the kinematic equation in terms of velocities, acceleration, and distance.

$\begin{array}{rcl} {V_{f}}^{2} & = & {V^{2}}_{i} + 2 a ∆ y \\ 0 & = & {(Vsin (55 °))}^{2} + 2 (- 9.8 m / s^{2}) (5.2 m) \\ Vsin (55 °) & = & \sqrt{2 (9.8 m / s^{2}) (5.2 m)} \\ V & = & \frac{10.1}{\sin (55 °)} \\ V & = & 12.3 m / s \end{array}$

Therefore, the initial velocity is $12.3 m / s$

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