A tie plate is used to transmit three-bar forces to a beam as shown in the figure. The modulus of the resultant R of the three forces is 100 kN. If the force F1 has a modulus of 20 kN, determine the moduli of the forces F2 and F3
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A: Given Steel plate thickness t = 12 mm Diameter of the bolt d = 20 mm Force…
Q: A wire having Young's modulus 1.2 × 10¹1 N/m² is subjected to the stress of 2.4 × 10¹ N/m². If the…
A: Given :- Young's modulus Y = 1.2*1011 N/m2 stress σ = 2.4 × 107 N/m². length l = 10m
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A:
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A: Concept: To determine the Maximum Tension and Compression Bending Stress we will divide the Cross…
Q: Bulk modulus is defined as -P / (ΔV/V). Therefore it can be negative. True or False? a) True b)…
A: The Answer is False.
Q: The figure represents an insect caught at the midpoint of a spider-web thread. The thread breaks…
A: Given,breaking stress of the string, 9.2 ×108 N/m2strain, 2.00lengthh of the thread, L = 3.0 cmcross…
Q: A heavy crate with weight 4900 N hangs from a thick nylon rope. The rope has a cross-sectional area…
A: Solution: Given that Weight W = 4900 N Area A = 1.4x10-4 m2 youngs modulus E =3.7x109 N/m2
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Q: Question 3: Determine the force in each member of the truss and state if the members are in tension…
A: The forces are given To find = If the members are in tension or compression .
Q: A man with a mass of 70.5 kg stands on one foot. His femur has a cross-sectional area of 8.00 cm and…
A: mass of man (m) = 70.5 kg weight (w) = m×g = 70.5×9.8= 690.9 N Cross sectional area of femur (A) = 8…
Q: Ropes for rock climbing have a diameter of 10.5 mm and a Young's modulus of 8.72x10 N/m2. If a rock…
A: Given: Diameter,d=10.5mm=10.5×10-3mRadius,r=5.25mm=5.25×10-3mYoung's…
Q: A femur bone of length 30 cm and diameter 2.5 cm is subjected to a compressive tress of 1.5 *10…
A: Given: Stress σ=1.5×108N/m2Young's modulus (Y)=1.5×1010N/mLength L=30cmDiameter d=2.5cm
Q: Humans can bite with a force of approximately 791 N. If a human tooth has the Young's modulus of…
A: The change in the tooth's lenght is 7.23×10-6 m.
Q: The cross-section of a hollow shaft subjected to a torque T is shown in the figure. Which point…
A: The answer to the above problem is given below
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A: Given information: The length of the rod, l=2.0 m The cross-sectional area of the rod, A=0.30…
Q: A uniform platform with mass M=30kg and length L=15m is placed on two supports as shown. The…
A: A mass of a uniform platform,
Q: Explain the tem bulk modulus.
A: The bulk modulus is defined as a constant that describes how resistant a substance is to stress. It…
Q: A solid copper cube has an edge length of 82.4 cm. How much stress must be applied to the cube to…
A: Given data- length of the side(L) = 0.824 m reduced side (L1 ) = 0.82 m…
Q: Calculate the Young's modulus for the given wire when a load of 2000 N is hung from the wire? The…
A: Write the equation for Young’s modulus of elasticity
Q: A particular human hair has a Young's modulus of 3.31 x 10° N/m2 and a diameter of 145 um. If a 236…
A:
Q: A 5.0 × 102-N object is hung from the end of a wire of a cross-sectional area of 0.010 cm2. The…
A: Given data: Force (F) = 5.0×102 N Cross-sectional area (A) = 0.010 cm2 = 0.010×10-4 m2 Original…
Q: Humans can bite with a force of approximately 810 N. If a human tooth has the Young's modulus of…
A: SOlution: as given F = 810 N E = youngs modulus of bone= A = 1.5 cm2 = 1.5x10-4 m2 L = 1.5 cm =…
Q: A steel cable 1.70 m in length and with cross-sectional radius 0.380 mm is used to suspend from the…
A: Length of cable (L) = 1.70 m cross sectional radisu (r) = 0.38 mm mass (m) = 20 kg angular speed =…
Q: A 90 kg construction worker stands 2.0 m from the right end of a 6.0 m long, 600 kg steel beam as…
A: First we find the tension in the cable . The forces acting are shown below: where m1 is the mass of…
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Q: If you bend a rod down, it compresses the lower side of the rod and stretches the top, resulting in…
A: It is given that,
Q: A wire of length L , area of cross section A is hanging from a fixed support. The length of the wire…
A:
Q: A 10.2 m long wire with a cross-sectional area of 0.126 cm2 stretches by 0.196 cm when a tensile…
A: The given values are, L=10.2 mA=0.126 cm2=0.126×10-4 m2∆L=0.196 cm=0.196×10-2 mF=6250 N
Q: The lower surface of metal cube, having each side of length 10 cm, is kept fixed and tangential…
A: We need to compute-Force applied (F)=?The data given as-Length (L)=10 cm=0.1 mDisplacement (x)=0.1…
Q: Assume Young's modulus for bone is 1.50 x 1010 N/m2. The bone breaks if stress greater than 1.50 x…
A: Given : Young's modulus for bone, Y = 1.50*1010 N/m2 Stress to break the bone, S =…
Q: Assume Young's modulus of a femure bone of an effective diameter 2.5 cm is 1.5 x1010 N/m2. The bone…
A: Given: A femur bone of an effective diameter 2.5 cm and it's Young's modulus = 1.5 × 1010 N/m2.…
Q: A sculpture weighing 10000N rest on a horizontal surface at the top of a 6.0-m- tall vertical…
A: Given The weight of the sculpture is Ws=10000 N. The height of the vertical pillar is h=6 m. The…
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