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A three-phase 1000 HP, 4160 V induction motor operates at an efficiency of 95% and a power factor of 0.85 lagging. If the motor is delivering the rated power to a load, Calculate P, Q, and IL. A 300 KVAR capacitor bank is added in parallel with motor, calculate the new line current. Draw the power triangle to demonstrate the power factor reduction. a) b) с) Notes: Rated motor power is 1000 HP. 1 HP = 746 watts. Pout Efficiency is defined as: 7 Pin

A three-phase 1000 HP, 4160 V induction motor operates at an efficiency of 95% and a power factor of 0.85 lagging. If the motor is delivering the rated power to a load, Calculate P, Q, and IL. A 300 KVAR capacitor bank is added in parallel with motor, calculate the new line current. Draw the power triangle to demonstrate the power factor reduction. a) b) с) Notes: Rated motor power is 1000 HP. 1 HP = 746 watts. Pout Efficiency is defined as: 7 Pin

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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**Problem Statement:** A three-phase 1000 HP, 4160 V induction motor operates at an efficiency of 95% and a power factor of 0.85 lagging. If the motor is delivering the rated power to a load: a) Calculate P, Q, and I<sub>L</sub>. b) A 300 kVAR capacitor bank is added in parallel with the motor. Calculate the new line current. c) Draw the power triangle to demonstrate the power factor reduction. **Notes:** - Rated motor power is 1000 HP. - 1 HP = 746 watts. - Efficiency is defined as: \( \eta = \frac{P_{\text{out}}}{P_{\text{in}}} \). **Explanation:** This problem involves calculations of active power (P), reactive power (Q), and line current (I<sub>L</sub>) for an induction motor. The effect of adding a capacitor bank on the line current and the power factor is also considered and represented by a power triangle.
Transcribed Image Text:**Problem Statement:** A three-phase 1000 HP, 4160 V induction motor operates at an efficiency of 95% and a power factor of 0.85 lagging. If the motor is delivering the rated power to a load: a) Calculate P, Q, and I<sub>L</sub>. b) A 300 kVAR capacitor bank is added in parallel with the motor. Calculate the new line current. c) Draw the power triangle to demonstrate the power factor reduction. **Notes:** - Rated motor power is 1000 HP. - 1 HP = 746 watts. - Efficiency is defined as: \( \eta = \frac{P_{\text{out}}}{P_{\text{in}}} \). **Explanation:** This problem involves calculations of active power (P), reactive power (Q), and line current (I<sub>L</sub>) for an induction motor. The effect of adding a capacitor bank on the line current and the power factor is also considered and represented by a power triangle.
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