A thin stream of water flows smoothly from a faucet and falls straight down. At one point, the water is flowing at a speed 1.23 m/s. At a lower point, the diameter of the stream has decreased by a factor of 0.895. What is the vertical distance h between these two points? U1

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**Problem Description:**

A thin stream of water flows smoothly from a faucet and falls straight down. At one point, the water is flowing at a speed of \( v_1 = 1.23 \, \text{m/s} \). At a lower point, the diameter of the stream has decreased by a factor of 0.895. What is the vertical distance \( h \) between these two points?

**Answer:**

\( h = \) \_\_\_\_\_\_\_\_

**Explanation:**

To solve for \( h \), you would typically use principles from fluid dynamics and kinematics. The conservation of mass (continuity equation) and the conservation of energy (Bernoulli's equation) are often involved.

This problem requires calculating the speed at the lower point and using the change in velocity to find the vertical distance. Here are some basic steps you might consider:

1. **Continuity Equation:**
   The flow rate must be constant, so you have:
   \[
   A_1 v_1 = A_2 v_2
   \]
   where \( A_1 \) and \( A_2 \) are the cross-sectional areas at the two points. If the diameter decreases by a factor of 0.895, then:
   \[
   A_2 = (0.895)^2 A_1
   \]
   
2. **Find \( v_2 \):**
   By substituting the area relationship into the continuity equation, you can solve for \( v_2 \).

3. **Bernoulli’s Equation:**
   Relate the velocities and the height:
   \[
   v_1^2 + 2gh_1 = v_2^2 + 2gh_2
   \]
   Usually, you consider the difference in height (\( h = h_2 - h_1 \)) and solve for \( h \).

By following these principles, you can calculate the vertical distance \( h \) as the water accelerates due to gravity.
Transcribed Image Text:**Problem Description:** A thin stream of water flows smoothly from a faucet and falls straight down. At one point, the water is flowing at a speed of \( v_1 = 1.23 \, \text{m/s} \). At a lower point, the diameter of the stream has decreased by a factor of 0.895. What is the vertical distance \( h \) between these two points? **Answer:** \( h = \) \_\_\_\_\_\_\_\_ **Explanation:** To solve for \( h \), you would typically use principles from fluid dynamics and kinematics. The conservation of mass (continuity equation) and the conservation of energy (Bernoulli's equation) are often involved. This problem requires calculating the speed at the lower point and using the change in velocity to find the vertical distance. Here are some basic steps you might consider: 1. **Continuity Equation:** The flow rate must be constant, so you have: \[ A_1 v_1 = A_2 v_2 \] where \( A_1 \) and \( A_2 \) are the cross-sectional areas at the two points. If the diameter decreases by a factor of 0.895, then: \[ A_2 = (0.895)^2 A_1 \] 2. **Find \( v_2 \):** By substituting the area relationship into the continuity equation, you can solve for \( v_2 \). 3. **Bernoulli’s Equation:** Relate the velocities and the height: \[ v_1^2 + 2gh_1 = v_2^2 + 2gh_2 \] Usually, you consider the difference in height (\( h = h_2 - h_1 \)) and solve for \( h \). By following these principles, you can calculate the vertical distance \( h \) as the water accelerates due to gravity.
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