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A thin, smooth rod with a mass of 0.012 kg and a length of 50 cm is attached to the base by a frictionless hinge at point a. The bar is in a uniform magnetic field given as B = 0,25 T towards the plane of the page. What is the value of the current flowing in Ampers when the bar makes an angle of 30° with the horizontal? Take g=10 m/s?; sin 30° = cos60° = 0,5; sin60° = cos30° = v3/2

A thin, smooth rod with a mass of 0.012 kg and a length of 50 cm is attached to the base by a frictionless hinge at point a. The bar is in a uniform magnetic field given as B = 0,25 T towards the plane of the page. What is the value of the current flowing in Ampers when the bar makes an angle of 30° with the horizontal? Take g=10 m/s?; sin 30° = cos60° = 0,5; sin60° = cos30° = v3/2

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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14) y B X X X X X X X X XX X X XX X X X X X X X X X Xx \x x X а A thin, smooth rod with a mass of 0.012 kg and a length of 50 cm is attached to the base by a frictionless hinge at point a. The bar is in a uniform magnetic field given as B = 0,25 T towards the plane of the page. What is the value of the current flowing in Ampers when the bar makes an angle of 30° with the horizontal? Take g=10 m/s?; sin 30° = cos60° = 0,5; sin60° = cos30° = V3/2 a) I = 2,31 b) I = 1,30 c) I = 8,31 × 10-1 d) I = 5,77 x 10-1 e) I = 4,24 × 10-1
Transcribed Image Text:14) y B X X X X X X X X XX X X XX X X X X X X X X X Xx \x x X а A thin, smooth rod with a mass of 0.012 kg and a length of 50 cm is attached to the base by a frictionless hinge at point a. The bar is in a uniform magnetic field given as B = 0,25 T towards the plane of the page. What is the value of the current flowing in Ampers when the bar makes an angle of 30° with the horizontal? Take g=10 m/s?; sin 30° = cos60° = 0,5; sin60° = cos30° = V3/2 a) I = 2,31 b) I = 1,30 c) I = 8,31 × 10-1 d) I = 5,77 x 10-1 e) I = 4,24 × 10-1
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