A thin rod of mass M and length L is rotating counter-clockwise, with angular speed wo, about a fixed pivot point as seen in the figure below. Before m vo M, L Pivot Wo After 200 m y Pivot M,L X As the rod rotates into the position seen in the figure, it is struck by a right-traveling object of mass m moving with speed vo. (a) Using the coordinate system seen in the figure, what is the angular momentum vector of the rod-object system prior to the collision? (b) Suppose, after the collision, the object travels to the left with speed 200. What is the final angular speed of the rod?

icon
Related questions
Question
### Rotation Dynamics - Problem 3

**Problem Statement:**
A thin rod of mass \( M \) and length \( L \) is rotating counter-clockwise, with angular speed \( \omega_0 \), about a fixed pivot point as seen in the figure below.

#### Diagram Description:
- **Before Collision:**
  The rod is positioned vertically along the y-axis. The system is described as follows:
  - Mass \( m \) is an object moving to the right with a speed \( v_0 \).
  - The rotation pivot is at the origin of the coordinate system (0,0).
  - The rod's angular speed is \( \omega_0 \).

- **After Collision:**
  - The mass \( m \) travels to the left with a speed \( 2v_0 \) after collision.
  - The rod and its specifications (mass \( M \), length \( L \)) remain the same.

#### Questions:
(a) Using the coordinate system seen in the figure, what is the angular momentum vector of the rod-object system prior to the collision?

(b) Suppose, after the collision, the object travels to the left with speed \( 2v_0 \). What is the final angular speed of the rod?

#### Solution Overview:
- **Angular Momentum Analysis before Collision:**
  - Consider contributions from both the rotating rod and the moving mass \( m \).

- **Angular Momentum Conservation:**
  - Apply conservation principles to ascertain the final angular speed of the rod after the collision.

### Detailed Solution:

#### (a) Angular Momentum before Collision

The angular momentum \( \vec{L}_{\text{initial}} \) of the system before the collision is the sum of the angular momentum of the rod and the angular momentum of the object \( m \).

1. **Rod (Rotating about Pivot):**
   - Moment of inertia \( I_{\text{rod}} = \frac{1}{3}ML^2 \)
   - Angular momentum \( \vec{L}_{\text{rod}} = I_{\text{rod}} \cdot \omega_0 = \frac{1}{3}ML^2 \omega_0 \)

2. **Object \( m \) (Moving with speed \( v_0 \)):**
   - Position vector \( \vec{r} = L \hat{i} \) (since it's moving along the x-axis)
   - Linear
Transcribed Image Text:### Rotation Dynamics - Problem 3 **Problem Statement:** A thin rod of mass \( M \) and length \( L \) is rotating counter-clockwise, with angular speed \( \omega_0 \), about a fixed pivot point as seen in the figure below. #### Diagram Description: - **Before Collision:** The rod is positioned vertically along the y-axis. The system is described as follows: - Mass \( m \) is an object moving to the right with a speed \( v_0 \). - The rotation pivot is at the origin of the coordinate system (0,0). - The rod's angular speed is \( \omega_0 \). - **After Collision:** - The mass \( m \) travels to the left with a speed \( 2v_0 \) after collision. - The rod and its specifications (mass \( M \), length \( L \)) remain the same. #### Questions: (a) Using the coordinate system seen in the figure, what is the angular momentum vector of the rod-object system prior to the collision? (b) Suppose, after the collision, the object travels to the left with speed \( 2v_0 \). What is the final angular speed of the rod? #### Solution Overview: - **Angular Momentum Analysis before Collision:** - Consider contributions from both the rotating rod and the moving mass \( m \). - **Angular Momentum Conservation:** - Apply conservation principles to ascertain the final angular speed of the rod after the collision. ### Detailed Solution: #### (a) Angular Momentum before Collision The angular momentum \( \vec{L}_{\text{initial}} \) of the system before the collision is the sum of the angular momentum of the rod and the angular momentum of the object \( m \). 1. **Rod (Rotating about Pivot):** - Moment of inertia \( I_{\text{rod}} = \frac{1}{3}ML^2 \) - Angular momentum \( \vec{L}_{\text{rod}} = I_{\text{rod}} \cdot \omega_0 = \frac{1}{3}ML^2 \omega_0 \) 2. **Object \( m \) (Moving with speed \( v_0 \)):** - Position vector \( \vec{r} = L \hat{i} \) (since it's moving along the x-axis) - Linear
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps

Blurred answer