A thin glass rod of radius R and length L carries a uniform surface charge s. It is set spinning about its axis, at an angular velocity w. Find the magnetic field at a distance s>>R from the center of the rod. I'm asking again to the person who answered the question. How did he come up with the dB equation, could he please elaborate the answer? How can we write the z = cosθ - sinθ?

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A thin glass rod of radius R and length L carries a uniform surface charge s. It is set spinning about its axis, at an angular velocity w. Find the magnetic field at a distance s>>R from the center of the rod.

I'm asking again to the person who answered the question. How did he come up with the dB equation, could he please elaborate the answer? How can we write the z = cosθ - sinθ?

We have,
î = cos of – sin 00
dB=22 · (2 cos Of + sin 0 ô
Ho dm
4x 3
dB= d (3 cos? 0 – 1)
2x 3
where, dm = (GRodz) (R² n)
dz = -s cot0
dz =
OP-
sin 0
r =
sin e
Transcribed Image Text:We have, î = cos of – sin 00 dB=22 · (2 cos Of + sin 0 ô Ho dm 4x 3 dB= d (3 cos? 0 – 1) 2x 3 where, dm = (GRodz) (R² n) dz = -s cot0 dz = OP- sin 0 r = sin e
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