A thin film having an index of refraction of 1.50 is surrounded by air. It is illuminated normally by white light. Analysis of the reflected light shows that the wavelengths 360, 450, and 602 are the only missing wavelengths in or near the visible portion of the spectrum. That is, for those wavelengths, there is destructive interference. What is the thickness of the film? (Give your answer in nm.)

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A thin film having an index of refraction of 1.50 is surrounded by air. It is illuminated normally by white light. Analysis of the reflected light shows that the wavelengths 360, 450, and 602 are the only missing wavelengths in or near the visible portion of the spectrum. That is, for those wavelengths, there is destructive interference. What is the thickness of the film? (Give your answer in nm.)

Expert Solution
Step 1

Given that,

The refractive index of the film n=1.50

The destructive interference is found for the wavelength

λ1=360 nm    =360 nm×1 m109 nm=360×10-9 m

The destructive wavelength for the second wavelength 

λ2=450 nm    =450 nm×1 m109 nm=450×10-9 m

The destructive interference for the third wavelength

λ3=602 nm    =602 nm×1 m109 nm=602×10-9 m

 

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