A thermometer is taken from an inside room to the outside, where the air temperature is -12" C. After 3 minutes the thermometer reads 5" C and after 5 minutes it reads -3" C. In order to describe this problem, we use the following Initial Value Problem: Select one: dT dt = k(T+ 3), T(3) = 5, T(5) = -12 %3D O = k(T- 5), T(3) = -12, T(5) = -3 = k(T- 12), T(3) = 5, T(5) = -3 %3D = k(T + 12), T(3) = 5, T(5) = -3 O None of them
A thermometer is taken from an inside room to the outside, where the air temperature is -12" C. After 3 minutes the thermometer reads 5" C and after 5 minutes it reads -3" C. In order to describe this problem, we use the following Initial Value Problem: Select one: dT dt = k(T+ 3), T(3) = 5, T(5) = -12 %3D O = k(T- 5), T(3) = -12, T(5) = -3 = k(T- 12), T(3) = 5, T(5) = -3 %3D = k(T + 12), T(3) = 5, T(5) = -3 O None of them
Chapter10: Exponential And Logarithmic Functions
Section10.5: Solve Exponential And Logarithmic Equations
Problem 10.85TI: Hector invests $10,000 at age 21. He hopes the investments will be worth when he turns 50. If the...
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Question
![A thermometer is taken from an inside room to the outside, where the air temperature is -12" C.
After 3 minutes the thermometer reads 5" C and after 5 minutes it reads -3" C. In order to
describe this problem, we use the following Initial Value Problem:
Select one:
dT
dt
= k(T+ 3),
T(3) = 5, T(5) = -12
%3D
O = k(T- 5),
T(3) = -12, T(5) = -3
%3D
= k(T- 12), T(3) = 5, T(5) = -3
%3D
O 4 = k(T + 12), T(3) = 5, T(5) = -3
%3D
di
O None of them](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fab710075-8787-4c20-a083-aaec9d843e76%2F0cb2af5c-19ce-460b-aad0-0f8c2d4d30f4%2Fza658yi_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A thermometer is taken from an inside room to the outside, where the air temperature is -12" C.
After 3 minutes the thermometer reads 5" C and after 5 minutes it reads -3" C. In order to
describe this problem, we use the following Initial Value Problem:
Select one:
dT
dt
= k(T+ 3),
T(3) = 5, T(5) = -12
%3D
O = k(T- 5),
T(3) = -12, T(5) = -3
%3D
= k(T- 12), T(3) = 5, T(5) = -3
%3D
O 4 = k(T + 12), T(3) = 5, T(5) = -3
%3D
di
O None of them
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