A thermocouple produces an e.m.f. in mV according to the temperature difference between the sensor tip 0, and the reference junction 02 (also called gauge head where the reference junction is embedded inside the display unit for the thermocouple) such that e = a(0, – 0,) + B(e; – e; ) a = 3.5x10² mV/deg and B = 8.2x10* °mV/deg*. The gauge head is at 20°C. The output is 10 mV. Calculate the temperature of the sensor.
A thermocouple produces an e.m.f. in mV according to the temperature difference between the sensor tip 0, and the reference junction 02 (also called gauge head where the reference junction is embedded inside the display unit for the thermocouple) such that e = a(0, – 0,) + B(e; – e; ) a = 3.5x10² mV/deg and B = 8.2x10* °mV/deg*. The gauge head is at 20°C. The output is 10 mV. Calculate the temperature of the sensor.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Transcribed Image Text:A thermocouple produces an e.m.f. in mV according to the temperature difference between the
sensor tip 0, and the reference junction 02 (also called gauge head where the reference junction
is embedded inside the display unit for the thermocouple) such that
e = a(0, – 0,) + B(e; – e; )
a = 3.5x10? mv/deg and B = 8.2x106 mV/deg. The gauge head is at 20°C. The output is 10 mV.
Calculate the temperature of the sensor.
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Transcribed Image Text:A thermocouple produces an emf in mV according to the temperature difference between
the temperature at the sensor tip and the temperature at the gauge. Given a =3.5 x
nV
10-2 mV and 3=8.2 x 10-6 mV. Determine the mV output when the tip is 220°C and
the gauge head at 20°C.
C
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