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(a) The reverse saturation current of an npn-transistor, Is = 5.0 × 10¬12 mA and the common = 0.615 V . Calculate IB, Ic %D emitter current gain B = 125. The transistor is biased at VRE and Ig. (b) The BJT circuit is shown in Fig. 1 (b). Plot the output load line by assuming that ß and VBE (on) = 0.7 V. = 85 Vcc = 15 V Rc =0.5 kQ RB = 28 kQ VBB = 5 V o W + V BE RE = 420 N Fig. 1(b)

(a) The reverse saturation current of an npn-transistor, Is = 5.0 × 10¬12 mA and the common = 0.615 V . Calculate IB, Ic %D emitter current gain B = 125. The transistor is biased at VRE and Ig. (b) The BJT circuit is shown in Fig. 1 (b). Plot the output load line by assuming that ß and VBE (on) = 0.7 V. = 85 Vcc = 15 V Rc =0.5 kQ RB = 28 kQ VBB = 5 V o W + V BE RE = 420 N Fig. 1(b)

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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(a) The reverse saturation current of an npn-transistor, Is = 5.0 × 10¬12 mA and the common emitter current gain B = 125. The transistor is biased at VRE = 0.615 V . Calculate Ip, Ic and Ig. (b) The BJT circuit is shown in Fig. 1 (b). Plot the output load line by assuming that ß = 85 and VRE (on) = 0.7 V. Vcc = 15 V Rc = 0.5 kQ RB = 28 kQ %3D VBB =5 V o + V BE Re = 420 Q Fig. 1(b)
Transcribed Image Text:(a) The reverse saturation current of an npn-transistor, Is = 5.0 × 10¬12 mA and the common emitter current gain B = 125. The transistor is biased at VRE = 0.615 V . Calculate Ip, Ic and Ig. (b) The BJT circuit is shown in Fig. 1 (b). Plot the output load line by assuming that ß = 85 and VRE (on) = 0.7 V. Vcc = 15 V Rc = 0.5 kQ RB = 28 kQ %3D VBB =5 V o + V BE Re = 420 Q Fig. 1(b)
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