(a) The positively charged particle shown in the diagram at left creates an electric field E, at location A. a h g j zero magnitude What is the direction of E, at location A? (Refer to the rosette above.) ---Select-- v (b) Now a block of metal is placed in the location shown by the dashed rectangle. a h b g j zero magnitude What is the direction of the electric field Em at location A due only to the charges in and/or on the metal block? (Refer to the rosette above.) ---Select-- v (c) With the metal block still in place, what is the direction of the net electric field at location A? Select--- v (d) With the metal block still in place, what is the magnitude of E,, the field due only to the charged particle? O JĒ,I is the same as it was originally, without the block. O JE, is zero, because the electric field due to the particle can't go through the block. O IE,I is less than it was originally, because the block is in the way.

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(a) The positively charged particle shown in the diagram at left creates an electric field E, at location A.
j zero magnitude
What is the direction of E, at location A? (Refer to the rosette above.)
|---Select--- v
(b) Now a block of metal is placed in the location shown by the dashed rectangle.
A
j zero magnitude
What is the direction of the electric field Em at location A due only to the charges in and/or on the metal block? (Refer to the rosette above.)
|---Select--- v
(c) With the metal block still in place, what is the direction of the net electric field at location A?
|---Select--- v
(d) With the metal block still in place, what is the magnitude of E,, the field due only to the charged particle?
O JE,I is the same as it was originally, without the block.
O JĒ,I is zero, because the electric field due to the particle can't go through the block.
O JE,| is less than it was originally, because the block is in the way.
Transcribed Image Text:(a) The positively charged particle shown in the diagram at left creates an electric field E, at location A. j zero magnitude What is the direction of E, at location A? (Refer to the rosette above.) |---Select--- v (b) Now a block of metal is placed in the location shown by the dashed rectangle. A j zero magnitude What is the direction of the electric field Em at location A due only to the charges in and/or on the metal block? (Refer to the rosette above.) |---Select--- v (c) With the metal block still in place, what is the direction of the net electric field at location A? |---Select--- v (d) With the metal block still in place, what is the magnitude of E,, the field due only to the charged particle? O JE,I is the same as it was originally, without the block. O JĒ,I is zero, because the electric field due to the particle can't go through the block. O JE,| is less than it was originally, because the block is in the way.
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Positive charge and its electric field lines

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