(a) The matrix A11 is 8 (b) The determinant of the matrix A₁1 is det A11 = (c) The matrix A12 is

Advanced Engineering Mathematics
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Chapter2: Second-order Linear Odes
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**Finding the Determinant of a Matrix Using Minors**

To find the determinant of the matrix \( A \):

\[
A = \begin{bmatrix} -6 & -3 & -9 \\ 6 & 8 & -1 \\ -7 & 7 & -1 \end{bmatrix}
\]

We will use the method of minors by expanding along the first row.

### Formula for Determinant Using Minors

The formula for \(\det A\) by expanding along the first row is:

\[
\det A = (-6 \times \det A_{11}) - (-3 \times \det A_{12}) + (-9 \times \det A_{13})
\]

where \(A_{11}\), \(A_{12}\), and \(A_{13}\) are appropriate submatrices of the matrix \(A\).

#### (a) The Matrix \(A_{11}\)

- **Diagram Area**: A placeholder for the 2x2 submatrix \( A_{11} \).

#### (b) The Determinant of the Matrix \(A_{11}\)

- **Formula Placeholder**: \(\det A_{11} =\) [Calculation to be done]

#### (c) The Matrix \(A_{12}\)

- **Diagram Area**: A placeholder for the 2x2 submatrix \( A_{12} \).

#### (d) The Determinant of the Matrix \(A_{12}\)

- **Formula Placeholder**: \(\det A_{12} =\) [Calculation to be done] 

> By calculating each of these determinants and substituting back into the original formula, you can derive the overall determinant of matrix \(A\).
Transcribed Image Text:**Finding the Determinant of a Matrix Using Minors** To find the determinant of the matrix \( A \): \[ A = \begin{bmatrix} -6 & -3 & -9 \\ 6 & 8 & -1 \\ -7 & 7 & -1 \end{bmatrix} \] We will use the method of minors by expanding along the first row. ### Formula for Determinant Using Minors The formula for \(\det A\) by expanding along the first row is: \[ \det A = (-6 \times \det A_{11}) - (-3 \times \det A_{12}) + (-9 \times \det A_{13}) \] where \(A_{11}\), \(A_{12}\), and \(A_{13}\) are appropriate submatrices of the matrix \(A\). #### (a) The Matrix \(A_{11}\) - **Diagram Area**: A placeholder for the 2x2 submatrix \( A_{11} \). #### (b) The Determinant of the Matrix \(A_{11}\) - **Formula Placeholder**: \(\det A_{11} =\) [Calculation to be done] #### (c) The Matrix \(A_{12}\) - **Diagram Area**: A placeholder for the 2x2 submatrix \( A_{12} \). #### (d) The Determinant of the Matrix \(A_{12}\) - **Formula Placeholder**: \(\det A_{12} =\) [Calculation to be done] > By calculating each of these determinants and substituting back into the original formula, you can derive the overall determinant of matrix \(A\).
(c) The matrix \( A_{12} \) is  
\[ 
\begin{bmatrix} 
& \\ 
& 
\end{bmatrix} 
\]

(d) The determinant of the matrix \( A_{12} \) is  
\[ 
\text{det. } A_{12} = \underline{\hspace{2cm}} 
\]

(e) The matrix \( A_{13} \) is  
\[ 
\begin{bmatrix} 
& \\ 
& 
\end{bmatrix} 
\]

(f) The determinant of the matrix \( A_{13} \) is  
\[ 
\text{det. } A_{13} = \underline{\hspace{2cm}} 
\]

(g) The determinant of the matrix \( A \) is  
\[ 
\text{det. } A = \underline{\hspace{2cm}} 
\]

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Transcribed Image Text:(c) The matrix \( A_{12} \) is \[ \begin{bmatrix} & \\ & \end{bmatrix} \] (d) The determinant of the matrix \( A_{12} \) is \[ \text{det. } A_{12} = \underline{\hspace{2cm}} \] (e) The matrix \( A_{13} \) is \[ \begin{bmatrix} & \\ & \end{bmatrix} \] (f) The determinant of the matrix \( A_{13} \) is \[ \text{det. } A_{13} = \underline{\hspace{2cm}} \] (g) The determinant of the matrix \( A \) is \[ \text{det. } A = \underline{\hspace{2cm}} \] Buttons: - Calculator - Check Answer
Expert Solution
Step 1

given matrix 

A=-6-3-9-68-1-7-7-1

(a) find matrix A11

A11=8-1-7-1

(b) determinant of matrix A11

A11=8-1-7-1          =8-1--1-7          =-8-7          =-15

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