a) The current through a pure capacitor is given by i = 28.28cos(314t). Derive an expression for the voltage across the capacitor in the form v = Vm cos(wt) and comment on your answer.
a) The current through a pure capacitor is given by i = 28.28cos(314t). Derive an expression for the voltage across the capacitor in the form v = Vm cos(wt) and comment on your answer.
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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a) The current through a pure capacitor is given by
i = 28.28cos(314t).
Derive an expression for the voltage across the capacitor in the form v = Vm cos(wt) and comment on your answer.
b)Estimate the value of the current I and the voltage V in each of the circuits shown in Figure QA1(c) and justify your method of estimation.

Transcribed Image Text:F = 40 kN
x = 0
x = 0.5 m
Figure QB2.1
z =
Neutral axis
.아
z = /2
Figure QB2.2

Transcribed Image Text:A bending test is performed on the supported beam in figure QB2.1. The length of the beam is L=1 m,
and a vertical concentrated load of 40 kN is applied in the middle section of the beam (i.e. x = 0.5 m),
providing a symmetric inflection of the beam, with the maximum vertical displacement located at the
middle section. The beam has a rectangular cross-section with a thickness h = 0.08 m, and a width
b = 0.06 m. The beam is made of steel with Young's modulus of 200 GPa. In figure QB2.2 a close-up
on the middle section is shown. The vertical z axis indicates the coordinates along the thickness
dimension at the middle section, with z = 0 on the neutral axis. Assume that cross-sections initially
planar and normal to the neutral axis remain planar and normal to the neutral axis after the bending.
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