A textile dye has the following % composition: 75.95% C 17.72% N 6.33% H If the molar mass of the dye is around 240 g/mol, what steps need to be taken to calculate the empirical and molecular formula?

Q: A substance composed of only N and O has the composition by mass 69.57% O. What is the molecular…

A: Molecular formula of the compound can be determined by calculating the number of moles of all the…

Q: Oxalic acid is found to have the following composition: 26.7% C, 71.1 % O, and 2.2 % H.   The…

A: Element % composition Atomic Mass Relative composition = % compositionAtomic mass Simplest ratio…

Q: Determine the empirical and molecular formula for a compound that gives the following percentages…

A: Assuming we have 1 mole of compound Hence mass of compound = 1 X molar mass = 98.96 g Since the mass…

Q: A compound consisting of B, N, and H undergoes elemental analysis. The % composition by mass is…

A: Given,Percent of B in the compound = 40.28 %Percent of N in the compound = 52.20 %Percent of H in…

Q: The compound chloral hydrate, known in detective stories as knockout drops, is composed of 14.52% C,…

A: The empirical formula of a compound gives the proportions of the elements present in the compound.…

Q: Mandelic acid is an organic acid composed of carbon (63.15%), hydrogen ( 5.30%), and oxygen…

A:

Q: What is the empirical formula for a compound that contains 0.063 mol chlorine and 0.22 mol oxygen?…

A: [1.]   Number of moles of Chlorine = 0.063 mol  Number of moles of oxygen  = 0.22 mol  On taking the…

Q: Determine the empirical formula of a compound with the following composition by mass: 18.0%C, 2.5%H,…

A: We have to predict the empirical formula.

Q: Calculate the empirical and molecular formulas of a compound from percentage composition and…

A: Let us solved the problem by taking an example accordingly. Let us suppose a sample has 45% of…

Q: Opal is a hydrated form of silica. If a laboratory analysis of a sample of opal reveals it to…

A: Hydrated form of silica means some of water molecules are present in form of H2O in silica compound.

Q: An unknown compound has a % composition of 54.53% carbon, 9.153% hydrogen, and 36.32% oxygen. If the…

A:

Q: A fertilizer is found to have the follow- ing mass percentage composition: 12.2% N, 5.26% H, 26.9%…

A: Given that:                 Mass percentage of nitrogen = 12.2 %                    Mass percentage…

Q: What is the empirical formula of a compound composed of 72.36% Fe and 27.64% O by mass?

A: Empirical Formula :-  Empirical formula is the simplest ratio of number of atoms present in a…

Q: A sample of compound X is subjected to elemental analysis and the following percentages by weight…

A: Given   % C = 39.97 %  % H  =  6.73 %  % O  =  53.30  Empirical formula = ?

Q: The percentage composition of an organic compound CxHyOz is 40.00 % C, 6.73 % H and 53.27 % O. Its…

A: Lets suphose the compound has moler mass = 100g/mol So, there is 40g c , 6.73 g  and 53·27 g.40g…

Q: An organic compound contains 24.24 % Carbon, 4.04 % Hydrogen, and 71.72 % Chlorine. What is its…

A: Given, Mass % of carbon (C) = 24.24 % = 24.24 g Mass % of hydrogen (H) = 4.04 % = 4.04 g Mass % of…

Q: What is the empirical formula of a compound composed of 81.71% C and 18.29% H by mass?

A: Let mass of compound = 100gTherefore,  Grams of C = 81.71 gGrams of H = 18.29 g

Q: What is the empirical formula of a compound with the following composition: 24.78% C, 1.05% H, and…

A: Empirical formula can be calculated by these steps dividing mass percent with molar mass to get…

Q: A substance was found by analysis to contain 45.57% tin and 54.43% chlorine. What is the empirical…

A: In the given question we have to find out the empherical formula of the following substance.

Q: A compound is known to consist solely of carbon, hydrogen, and oxygen. Through elemental analysis,…

A: Given:Percentage of Carbon = 26.68%Percentage of Hydrogen = 2.24%Percentage of oxygen =…

Q: empirical formula of C2H3O and a molecular weight of 129 g/mole, what is its molecular formula

A: Empirical formula = C2H3O Empirical formula mass = 2×12 + 3×1 +1×16 = 43 g/mol Molecular weight =…

Q: The percentage composition by mass of benzene is 92.2% carbon and 7.8 % hydrogen. What is the…

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Q: Determine the empirical formula for a compound that is 76.6%76.6% C, 6.4%6.4% H, and 17.0%17.0% O by…

A: Given that the mass percent of C, H and O is 76.6%, 6.4% and 17.0% respectively. Number of moles of…

Q: A compound is 7.7% (by mass) hydrogen and 92.7 % carbon. It has a molecular weight of 52 g/mole.…

A: Empirical formula are the formula which represent simplest ratio of an element present in a given…

Q: A compound with an empirical formula of C4H4O and a molar mass of 136 grams per mole. What is the…

A: Given, Compound With an empirical formula = C4H4O  molar mass of the compound = 136 g/mol Molecular…

Q: In a first expirement, a compound is analyzed and found to contain 85.63% C and 14.37% hydrogen by…

A: 1. atom % in samp;e mole Mole ratio (divided by smallest number of moles) C 85.63 85.63 /12 =…

Q: Two compounds have the same composition: 92.25% C and 7.75% H . Obtain the empirical formula…

A: Given data, C = 92.25% H = 7.75% The molecular weight of one of the compound = 26.02 amu The…

Q: An organic acid contains 40.92% C, 54.50 % O, 4.58 % H, by mass. The molecular mass is 176 g/mole.…

A: We have given that  Molar mass = 176g/mole  Percent composition of C = 40.92%  Percent composition…

Q: What is the empirical formula for a compound that is 41.8% N, 24.7% C, 31.4% O, and 2.1% H by mass?…

A:

Q: An iron-containing compound is 20.1% Fe, 11.5% S, 63.3% O, and 5.1% H. What is the empirical formula…

A: Given,The elemental analysis report gives the 20.1% Fe, 11.5 % S, 63.3 % oxygen, and 5.1% hydrogen.…

Q: Give the empirical formula of the following compound if a sample contains 40.0% C, 6.7% H, and 53.3%…

A:

Q: An unknown compound has a molar mass of 236.7 g/mol. Given a percent composition by mass of 10.13%…

A:

Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.