A textile dye has the following % composition: 75.95% C 17.72% N 6.33% H If the molar mass of the dye is around 240 g/mol, what steps need to be taken to calculate the empirical and molecular formula?
A textile dye has the following % composition: 75.95% C 17.72% N 6.33% H If the molar mass of the dye is around 240 g/mol, what steps need to be taken to calculate the empirical and molecular formula?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
A textile dye has the following % composition:
75.95% C
17.72% N
6.33% H
If the molar mass of the dye is around 240 g/mol, what steps need to be taken to calculate the empirical and molecular formula?
Expert Solution
Step 1: Writing the given information
A textile dye has the following % composition:
mass % of C = 75.95% = 75.95 g
mass % of N = 17.72% = 17.72 g
mass % of H = 6.33% = 6.33 g
Molar mass of dye = 240 g/mol
Empirical formula = ?
Molecular formula = ?
Note:
molar mass of C = 12.0 g/mol
molar mass of H = 1.0 g/mol
molar mass of N = 14.0 g/mol
Empirical formula can be define as the simplest whole number ratio of atoms of the element present in the compound.
Molecular formula can be define as the actual whole number of atoms of the element present in the compound.
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