a test of Ho: µ = 60 against Ha: u > 60, the sample data yielded the test statistic z=1.84. Find and interpret the p-value for the test. E Click the icon to view a table of standard normal values ne p-value is p=| Round to three decimal places as needed.) terpret the results. What does this p-value mean? O A. The probability of observing a z-value < 1.84 is equal to the p-value, if µ> 60. O B. The probability of observing a z-value > 1.84 is equal to the p-value, if µ= 60. O C. The probability of observing a z-value < 1.84 is equal to the p-value, if p = 60. O D. The probability of observing a z-value > 1.84 is equal to the p-value, if µ> 60.

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
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Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Question

In a test of

H0​:
μ=60

against

Ha​:
μ>60​,

the sample data yielded the test statistic

z=1.84.

Find and interpret the​ p-value for the test.

---
### Hypothesis Testing Example

In a test of \( H_0: \mu = 60 \) against \( H_a: \mu > 60 \), the sample data yielded the test statistic \( z = 1.84 \). Find and interpret the p-value for the test.

#### Standard Normal Distribution Table
Click the icon to view a table of standard normal values.

#### P-Value Calculation
The p-value is \( p = \_\_\_\_\_ \).
(Round to three decimal places as needed.)

#### Interpretation of Results
What does this p-value mean?

- **Choice A:** The probability of observing a \( z \)-value \( < 1.84 \) is equal to the p-value, if \( \mu > 60 \).
- **Choice B:** The probability of observing a \( z \)-value \( > 1.84 \) is equal to the p-value, if \( \mu = 60 \).
- **Choice C:** The probability of observing a \( z \)-value \( < 1.84 \) is equal to the p-value, if \( \mu = 60 \).
- **Choice D:** The probability of observing a \( z \)-value \( > 1.84 \) is equal to the p-value, if \( \mu > 60 \).

---
Transcribed Image Text:--- ### Hypothesis Testing Example In a test of \( H_0: \mu = 60 \) against \( H_a: \mu > 60 \), the sample data yielded the test statistic \( z = 1.84 \). Find and interpret the p-value for the test. #### Standard Normal Distribution Table Click the icon to view a table of standard normal values. #### P-Value Calculation The p-value is \( p = \_\_\_\_\_ \). (Round to three decimal places as needed.) #### Interpretation of Results What does this p-value mean? - **Choice A:** The probability of observing a \( z \)-value \( < 1.84 \) is equal to the p-value, if \( \mu > 60 \). - **Choice B:** The probability of observing a \( z \)-value \( > 1.84 \) is equal to the p-value, if \( \mu = 60 \). - **Choice C:** The probability of observing a \( z \)-value \( < 1.84 \) is equal to the p-value, if \( \mu = 60 \). - **Choice D:** The probability of observing a \( z \)-value \( > 1.84 \) is equal to the p-value, if \( \mu > 60 \). ---
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