A tension member is to consist of two C10 channels and two PL1/2x11, arranged as shown in the Figure to support the service loads, D=200k and L=320k. The member is assumed to be 30ft long and is to have four lines of 4-in dia bolts. Assume U=0.85. All steel will be A36. Neglect block shear. 11 in (10

A tension member is to consist of two C10 channels and two PL1/2x11, arranged as shown in the Figure to support the service loads, D=200k and L=320k. The member is assumed to be 30ft long and is to have four lines of 4-in dia bolts. Assume U=0.85. All steel will be A36. Neglect block shear. 11 in (10

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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please solve 1.2
(See Attached picture of truss) 2. Since the reaction force at point A is 8975 #, The reaction force at point H is 7625#, the stress force in member AB is 14262 # (C), and the stress force in member BC is 11083# (T); calculate the minimum steel bolt size for attachment at points A and H. Use a factor of safety of 1.5 and a fitting factor of 1.15
Q2: Select a tension member is to consist of two C10 channels and two PL 1/2 x 11, arranged as shown in Figure below to support the service loads, PD= 200 k and PL= 320 k. The member is assumed to be 30 ft long and is to have four lines of 3/4-in Ø bolts. 30 degrees Assume U= 0.85. All steel will be A36. PL늘X1 C10 C10 11 in PL x 11 11 in
please solve 1.1
Problem For the frame shown, design the maximum permissible value of P with a factor of safety of 2.5. Design the maximum permissible value of P based on the following conditions: ✓ Ultimate tensile strength of each member CD is 300 ksi Ultimate shear strength of the bolts in A, C, E, and F is 200 ksi ✓ Ultimate bearing strength of member BDE is 150 ksi ✓ Ultimate bearing strength of the support plates is 250 ksi Members CD and BDE have cross-sectional dimensions of 5 in x 3 in (the larger dimension is the width). The diameters of the bolts are as follows: A and B - 1.5 in: C and D-2 in E and F - 1 in. 1.5 in. thick Support Plates -2 ft + D 3 ft B 2 in thick Support Mate Solution Step 1. Identify the conditions for design. Stress normal stress in each member CD, OCD shear stress in bolt A, TA shear stress in bolt C, T shear stress in bolt E, T shear stress in bolt F, T bearing stress on member BDE due to: bolt B, BDE-B bolt D, OBDE-D bolt E, OBDE-E bearing stress on support plates at…
J 6 The cast iron bearing seat in the picture is bolted to the steel beam of the ceiling bracket and supports the gravity load. Use M20 coarse thread ISO class 8.8 bolts with a thickness of 3.4 mm The steel washers are placed under the bolt head and nut. The flange of this bracket is 20 mm thick, the shaft The elastic modulus of the bearing is 135 GPa. (a) Assuming this is a permanent joint and the fasteners are lubricated when assembled, find the required wrench torque. (b) If the gravity load is 15 kN, try to find the load factor n of the design.
A double-angle shape, 2L7 3 4 3 3⁄8, is used as a tension member. The twoangles are connected to a gusset plate with 7⁄8-inch-diameter bolts throughthe 7-inch legs, as shown in Figure P3.4-5. A572 Grade 50 steel is used.a. Compute the design strength.b. Compute the allowable strength.
please solve 1.3
SOLVE FOR1 HR
The tension member shown in Figure 3.4-2 is a PL 5/8 x 10, and the steel is A36. The bolts are 7/8-inch in diameter. a. Determine the design strength for LRFD. b. Determine the allowable strength for ASD. | 2" +|+| in seinefrinehich 9 оо SO