A technician wraps wire around a tube of length 44 cm having a diameter of 7.0 cm. When the windings are evenly spread over the full length of the tube, the result is a solenoid containing 730 turns of wire. (b) If the current in this solenoid increases at the rate of +2.5 A/s, what is the self-induced emf in the solenoid?

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A technician wraps wire around a tube of length 44 cm having a diameter of 7.0 cm. When the windings are evenly spread over the full length of the tube, the result is a solenoid containing 730 turns of wire. (b) If the current in this solenoid increases at the rate of +2.5 A/s, what is the self-induced emf in the solenoid?

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Step 1

dia of tube = 7cm

length of wire = 44cm

therefore the number of turn N =730

self-inductance of coil L=μN2Al=4π×10-7×730×730×π×0.03520.44=0.00586 henry

 

 

 

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